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Full Discussion: Problem in getting data from a loop using grep and cut
Top Forums Shell Programming and Scripting Problem in getting data from a loop using grep and cut Post 302457983 by methyl on Wednesday 29th of September 2010 09:03:32 AM
Old 09-29-2010
The quick way:
Code:
grep \^"45" filename | cut -f3 -d+
000011481.00


Alternatively modifying your script to use a "while" not a "for" loop. There is never a reason to use a "for" loop with an open-ended list.
Also corrected various syntax anomalies. Note that "cut" either takes input from a pipeline or a file (in this case we need to use "echo" to get the record onto a pipeline).
Code:
cat filename | while read each_rec
do
  count=`echo "${each_rec}" | cut -c1-2`
  if [ ${count} -eq 45 ]
  then
       amount=`echo "${each_rec}" | cut -c24-35`
       echo "${amount}"
  fi
done
000011481.00

 

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LEARN ABOUT V7

zgrep

ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME

       zgrep - search possibly compressed files for a regular expression

SYNOPSIS

       zgrep [ grep_options ] [ -e ] pattern filename...

DESCRIPTION

       Zgrep  invokes  grep  on  compressed  or  gzipped  files.   These  grep	options  will  cause  zgrep  to  terminate  with  an  error  code:
       (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*).  All other options specified are passed directly to grep.  If no file is specified,  then  the
       standard input is decompressed if necessary and fed to grep.  Otherwise the given files are uncompressed if necessary and fed to grep.

       If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.

EXIT CODE

       2 - An option that is not supported was specified.

AUTHOR

       Charles Levert (charles@comm.polymtl.ca)

SEE ALSO

       grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)

																	  ZGREP(1)
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