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Shell Programming and Scripting
In Sed how can I replace starting from the 7th character to the 15th character.
Post 302455951 by rdcwayx on Wednesday 22nd of September 2010 08:39:16 PM
09-22-2010
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...
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sed searches a character string for a specified delimiter character, and returns a leading or traili
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LEARN ABOUT CENTOS
perl::critic::policy::builtinfunctions::prohibitlvaluesubstr
Perl::Critic::Policy::BuiltinFunctions::ProhibitLvalueSuUser(Contributed Perl DocumPerl::Critic::Policy::BuiltinFunctions::ProhibitLvalueSubstr(3) NAME
Perl::Critic::Policy::BuiltinFunctions::ProhibitLvalueSubstr - Use 4-argument "substr" instead of writing "substr($foo, 2, 6) = $bar". AFFILIATION
This Policy is part of the core Perl::Critic distribution. DESCRIPTION
Conway discourages the use of "substr()" as an lvalue, instead recommending that the 4-argument version of "substr()" be used instead. substr($something, 1, 2) = $newvalue; # not ok substr($something, 1, 2, $newvalue); # ok The four-argument form of "substr()" was introduced in Perl 5.005. This policy does not report violations on code which explicitly specifies an earlier version of Perl (e.g. "use 5.004;"). CONFIGURATION
This Policy is not configurable except for the standard options. SEE ALSO
"substr" in perlfunc (or "perldoc -f substr"). "4th argument to substr" in perl5005delta AUTHOR
Graham TerMarsch <graham@howlingfrog.com> COPYRIGHT
Copyright (c) 2005-2011 Graham TerMarsch. All rights reserved. This program is free software; you can redistribute it and/or modify it under the same terms as Perl itself. perl v5.16.3 2014-06-09 Perl::Critic::Policy::BuiltinFunctions::ProhibitLvalueSubstr(3)