09-22-2010
In Sed how can I replace starting from the 7th character to the 15th character.
Hi All,
Was wondering how I can do the following....
I have a String as follows
"ACCTRL000005022RRWDKKEEDKDD...."
This string can be in a file called tail.out or in a Variable called $VAR2
Now I have another variable called $VAR1="000004785" (9 bytes long), I need the content of $VAR1 in the string $VAR2
Example:
VAR1=000004785
|
|
VAR2= "ACCTRL000005022RRWDKKEEDKDD...."
So it should look like...
VAR2= "ACCTRL000004785RRWDKKEEDKDD...."
I know this can be done by sed, but I need to know how to replace from the 7th character till the 15th character.
Any help would be appreaciated.
Thanks,
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GETS(3) Library Functions Manual GETS(3)
NAME
gets, fgets - get a string from a stream
SYNOPSIS
#include <stdio.h>
char *gets(char *s)
char *fgets(char *s, int n, FILE *stream)
DESCRIPTION
Gets reads a string into s from the standard input stream stdin. The string is terminated by a newline character, which is replaced in s
by a null character. Gets returns its argument.
Fgets reads n-1 characters, or up through a newline character, whichever comes first, from the stream into the string s. The last charac-
ter read into s is followed by a null character. Fgets returns its first argument.
SEE ALSO
puts(3), getc(3), scanf(3), fread(3), ferror(3).
DIAGNOSTICS
Gets and fgets return the constant pointer NULL upon end of file or error.
BUGS
Gets deletes a newline, fgets keeps it, all in the name of backward compatibility.
Gets is not present in the Minix-vmd C library for reasons that should be obvious. Use fgets instead.
7th Edition May 15, 1985 GETS(3)