Sponsored Content
Top Forums Shell Programming and Scripting Selecting a part of the text (regex pattern, awk, sed) Post 302455514 by rdcwayx on Tuesday 21st of September 2010 11:36:10 PM
Old 09-22-2010
Code:
TEXT=$(echo $LINE|awk '{print $2}' |xargs dirname||sed 's#^/##' )

 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

Selecting line ahead and next using AWK or SED

:confused: Good Day, I have this script that gets the archive names and the time it applies based on the alert log. The application of archives are of daily basis and usually many so having this script helps my job become easier. My problem is that when i get all the time stamps and... (1 Reply)
Discussion started by: ownins
1 Replies

2. Shell Programming and Scripting

RegEx for text pattern

Hi, Please help me write regex for text pattern like CONTACT PEOPLE:first_name1.last_name1,first_name2.last_name2,first_name3.last_name3, ...so on Any advice is Okay! Thanks in advance. (6 Replies)
Discussion started by: rider29
6 Replies

3. Shell Programming and Scripting

sed to awk (regex pattern) how?

Hello, I am trying to covert a for statement into a single awk script and I've got everything but one part. I also need to execute an external script when "not found", how can I do that ? for TXT in `find debugme -name "*.txt"` ;do FPATH=`echo $TXT | sed 's/\(.*\)\/\(.*\)/\1/'` how... (7 Replies)
Discussion started by: TehOne
7 Replies

4. UNIX for Dummies Questions & Answers

blank space in regex pattern using sed

why does sed 's/.* //' show the last word in a line and sed 's/ .*//' show the first word in a line? How is that blank space before or after the ".*" being interpreted in the regex? i would think the first example would delete the first word and the next example would delete the second... (1 Reply)
Discussion started by: glev2005
1 Replies

5. Shell Programming and Scripting

Using Sed to remove part of line with regex

Greetings everyone. Right now I am working on a script to be used during automated deployment of servers. What I have to do is remove localhost.localdomain and localhost6.localdomain6 from the /etc/hosts file. Simple, right? Except most of the examples I've found using sed want to delete the entire... (4 Replies)
Discussion started by: msarro
4 Replies

6. Shell Programming and Scripting

Selecting specific 'id's from lines and columns using 'SED' or 'AWK'

Hello experts, I am new to this group and to 'SED' and 'AWK'. I have data (text file) with 5 columns (C_1-5) and 100s of lines (only 10 lines are shown below as an example). I have to find or select only the id numbers (C-1) of specific lines with '90' in the same line (of C_3) AND with '20' in... (6 Replies)
Discussion started by: kamskamu
6 Replies

7. Shell Programming and Scripting

Replacing part of a pattern in sed

Hi I have a piece of xml that has a pattern like this <int>159</int><int>30</int> I want to find this pattern but only substitute the second part of the pattern to {rid1}. Is that possible in sed ? Thanks. ---------- Post updated at 12:10 PM ---------- Previous update was at 12:01 PM... (11 Replies)
Discussion started by: vnn
11 Replies

8. Shell Programming and Scripting

SED: Pattern repitition regex matching

Fairly straightforward, but I'm having an awful time getting what I thought was a simple regex to work. I'll give the command I was playing with, and I'm aware why this one doesn't work (the 1,3 is off the A-Z, not the whole expression), I just don't know what the fix is: Actual Output(s): $... (5 Replies)
Discussion started by: Vryali
5 Replies

9. Shell Programming and Scripting

Regex in sed to find specific pattern and assign to variable

(5 Replies)
Discussion started by: radioactive9
5 Replies

10. UNIX for Advanced & Expert Users

sed REGEX to print multiple occurrences of a pattern from a line

I have a line that I need to parse through and extract a pattern that occurs multiple times in it. Example line: getInfoCall: info received please proceed, getInfoCall: info received please proceed, getInfoCall: info received please proceed, getInfoCall: info received please proceed,... (4 Replies)
Discussion started by: Vidhyaprakash
4 Replies
Devel::Refcount(3pm)					User Contributed Perl Documentation				      Devel::Refcount(3pm)

NAME
"Devel::Refcount" - obtain the REFCNT value of a referent SYNOPSIS
use Devel::Refcount qw( refcount ); my $anon = []; print "Anon ARRAY $anon has " . refcount($anon) . " reference "; my $otherref = $anon; print "Anon ARRAY $anon now has " . refcount($anon) . " references "; DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value. FUNCTIONS
$count = refcount($ref) Returns the reference count of the object being pointed to by $ref. COMPARISON WITH SvREFCNT This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed, whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH, CODE, GLOB and Regexp types) as well. Consider the following example program: use Devel::Peek qw( SvREFCNT ); use Devel::Refcount qw( refcount ); sub printcount { my $name = shift; printf "%30s has SvREFCNT=%d, refcount=%d ", $name, SvREFCNT($_[0]), refcount($_[0]); } my $var = []; printcount 'Initially, $var', $var; my $othervar = $var; printcount 'Before CODE ref, $var', $var; printcount '$othervar', $othervar; my $code = sub { undef $var }; printcount 'After CODE ref, $var', $var; printcount '$othervar', $othervar; This produces the output Initially, $var has SvREFCNT=1, refcount=1 Before CODE ref, $var has SvREFCNT=1, refcount=2 $othervar has SvREFCNT=1, refcount=2 After CODE ref, $var has SvREFCNT=2, refcount=2 $othervar has SvREFCNT=1, refcount=2 Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this case. Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it. After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the new anonymous CODE block. PURE-PERL FALLBACK An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in pure perl using the "B" module is used instead. This will behave identically, but is much slower. Rate pp xs pp 225985/s -- -66% xs 669570/s 196% -- SEE ALSO
o Test::Refcount - assert reference counts on objects AUTHOR
Paul Evans <leonerd@leonerd.org.uk> perl v5.14.2 2011-11-15 Devel::Refcount(3pm)
All times are GMT -4. The time now is 08:11 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy