given a relative path, how do i convert it into a full one. i.e. if i am in
/home/polypus
and i am given foo/bar then to get a full path i can just concatinate it with pwd, but what if i am given "../mama"
how do i programmatically convert:
/home/polypus and ../mama into ... (4 Replies)
Hi
I am trying to use sed to retrieve part of my html file's path. I am having a hard time getting what I want. Could someone give me some help?
I want to retrieve the section after html and before the file name
For example if I have the following, ... (3 Replies)
I have a text file with full list of files with their full path. I wanted to sort it by directory then files then subdirectory by alphabetically. When I used the sort command it doesn't give like what I want. Could somebody help me on this.
Here is the ex:
This is what I'm getting... (2 Replies)
Hi,
Is there a command that tells you right away the current working directory? I know the command "pwd", but that one gives the full path.
if pwd gives me:
/a/b/c/d/ggg/HERE
I want something that will give me:
HERE
Thanks,
Gaurab (13 Replies)
Hey
I'm new to the forums here, and I'm seeking help for this script that I'm writing. When I do ls -l of a directory it shows the full pathname for files in it. For example, if the directory is /internet/post/forum/ and the file is topic, it currently shows internet/post/forum/topic. What's the... (3 Replies)
I'm running AIX unix korn shell. If I echo $0, I only get the filename, it does not have the directory name also. So when I do: `dirname $0` it returns a . (meaning current directory). How get $0 to return the full path/filename? Do I need something in my .profile? Thank you. (8 Replies)
My input is as below :
/splunk/scrubbed/rebate/IFIND.REBTE.WROC.txt
/splunk/scrubbed/rebate/IFIND.REBTE.WROC.txt
/splunk/scrubbed/loyal/IFIND.HELLO.WROC.txt
/splunk/scrubbed/triumph/ifind.triumph.txt
From the above input I want to extract the file names only .
Basically I want to... (5 Replies)
Hello,
I am creating a file with all the source folders included in my git branch, when i grep for the used source, i found source included as relative path instead of absolute path, how can convert relative path to absolute path without changing directory to that folder and using readlink -f ? ... (4 Replies)
Discussion started by: Sekhar419
4 Replies
LEARN ABOUT PHP
ziparchive.open
ZIPARCHIVE.OPEN(3) 1 ZIPARCHIVE.OPEN(3)ZipArchive::open - Open a ZIP file archive
SYNOPSIS
mixed ZipArchive::open (string $filename, [int $flags])
DESCRIPTION
Opens a new zip archive for reading, writing or modifying.
PARAMETERS
o $filename
- The file name of the ZIP archive to open.
o $flags
- The mode to use to open the archive.
o ZipArchive::OVERWRITE
o ZipArchive::CREATE
o ZipArchive::EXCL
o ZipArchive::CHECKCONS
RETURN VALUES
o $Error codes
- Returns TRUE on success or the error code.
o ZipArchive::ER_EXISTS File already exists.
o ZipArchive::ER_INCONS Zip archive inconsistent.
o ZipArchive::ER_INVAL Invalid argument.
o ZipArchive::ER_MEMORY Malloc failure.
o ZipArchive::ER_NOENT No such file.
o ZipArchive::ER_NOZIP Not a zip archive.
o ZipArchive::ER_OPEN Can't open file.
o ZipArchive::ER_READ Read error.
o ZipArchive::ER_SEEK Seek error.
EXAMPLES
Example #1
Open and extract
<?php
$zip = new ZipArchive;
$res = $zip->open('test.zip');
if ($res === TRUE) {
echo 'ok';
$zip->extractTo('test');
$zip->close();
} else {
echo 'failed, code:' . $res;
}
?>
Example #2
Create an archive
<?php
$zip = new ZipArchive;
$res = $zip->open('test.zip', ZipArchive::CREATE);
if ($res === TRUE) {
$zip->addFromString('test.txt', 'file content goes here');
$zip->addFile('data.txt', 'entryname.txt');
$zip->close();
echo 'ok';
} else {
echo 'failed';
}
?>
PHP Documentation Group ZIPARCHIVE.OPEN(3)