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Full Discussion: Need help with script changing dates
Top Forums Shell Programming and Scripting Need help with script changing dates Post 302454555 by durden_tyler on Saturday 18th of September 2010 11:10:55 PM
Old 09-19-2010
Quote:
Originally Posted by bbraml
I am attempting to write a script where the user enters the month and day (two digit format). I am trying to have script will increase 6 more times (totaling 7). I am having issues with the script increasing by one ... i realized i couldnt get it to switch over to the next month if the search falls between the end of one and beginning of another month. ...
Here's an idea -

Code:
$ 
$ # change of month within 7 days from input
$ echo "2/26/2010" | perl -lne 'BEGIN {use DateTime} ($m,$d,$y)=split/\//;
                                $dt=DateTime->new(year=>$y,month=>$m,day=>$d);
                                for (0..6) {print $_,"\t",$dt->mdy("/"); $dt->add(days=>1)}'
0	02/26/2010
1	02/27/2010
2	02/28/2010
3	03/01/2010
4	03/02/2010
5	03/03/2010
6	03/04/2010
$ 
$ # the case of a leap year
$ echo "2/26/2008" | perl -lne 'BEGIN {use DateTime} ($m,$d,$y)=split/\//;
                                $dt=DateTime->new(year=>$y,month=>$m,day=>$d);
                                for (0..6) {print $_,"\t",$dt->mdy("/"); $dt->add(days=>1)}'
0	02/26/2008
1	02/27/2008
2	02/28/2008
3	02/29/2008
4	03/01/2008
5	03/02/2008
6	03/03/2008
$ 
$ # change of year within 7 days from input
$ echo "12/27/2009" | perl -lne 'BEGIN {use DateTime} ($m,$d,$y)=split/\//;
                                 $dt=DateTime->new(year=>$y,month=>$m,day=>$d);
                                 for (0..6) {print $_,"\t",$dt->mdy("/"); $dt->add(days=>1)}'
0	12/27/2009
1	12/28/2009
2	12/29/2009
3	12/30/2009
4	12/31/2009
5	01/01/2010
6	01/02/2010
$ 
$

tyler_durden
 

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LEARN ABOUT DEBIAN

datetime::format::epoch::dotnet

DateTime::Format::Epoch::DotNet(3pm)			User Contributed Perl Documentation		      DateTime::Format::Epoch::DotNet(3pm)

NAME

       DateTime::Format::Epoch::DotNet - Convert DateTimes to/from .NET epoch seconds

SYNOPSIS

	 use DateTime::Format::Epoch::DotNet;

	 my $dt = DateTime::Format::Epoch::DotNet->parse_datetime( 1051488000 );

	 DateTime::Format::Epoch::DotNet->format_datetime($dt);
	  # 1051488000

	 my $formatter = DateTime::Format::Epoch::DotNet->new();
	 my $dt2 = $formatter->parse_datetime( 1051488000 );
	 $formatter->format_datetime($dt2);

DESCRIPTION

       This module can convert a DateTime object (or any object that can be converted to a DateTime object) to the number of seconds since the
       epoch defined in the .NET Framework SDK.

       Note that this epoch is defined in the local time zone. This means that these two pieces of code will print the same number of seconds,
       even though they represent two datetimes 6 hours apart:

	   $dt = DateTime->new( year => 2003, month => 5, day => 2,
				time_zone => 'Europe/Amsterdam' );
	   print $formatter->format_datetime($dt);

	   $dt = DateTime->new( year => 2003, month => 5, day => 2,
				time_zone => 'America/Chicago' );
	   print $formatter->format_datetime($dt);

METHODS

       Most of the methods are the same as those in DateTime::Format::Epoch.  The only difference is the constructor.

       o   new()

	   Constructor of the formatter/parser object. It has no parameters.

SUPPORT

       Support for this module is provided via the datetime@perl.org email list. See http://lists.perl.org/ for more details.

AUTHOR

       Eugene van der Pijll <pijll@gmx.net>

COPYRIGHT

       Copyright (c) 2003 Eugene van der Pijll.  All rights reserved.  This program is free software; you can redistribute it and/or modify it
       under the same terms as Perl itself.

SEE ALSO

       DateTime

       datetime@perl.org mailing list

perl v5.10.1							    2007-12-03				      DateTime::Format::Epoch::DotNet(3pm)
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