Hi folks,
Lets say I have the following text file:
name, lastname, 1234, name.lastname@test.com
name1, lastname1, name2.lastname2@test.com, 2345
name, 3456, lastname, name3.lastname3@test.com
4567, name, lastname, name4.lastname4@test.com
I now need the following output:
1234... (5 Replies)
greetings citizens of Unix.com
I am perplexed with an issue.
The issue is trying to print the last 5 characters of a string in PERL.
Below are demonstrated my daft attempts at performing the forementioned task.
$row =~ m/^.*(.....)\s$/;
$row =~ m/\w{5}\s*$/i;$row =~... (3 Replies)
Hi all,
This should be very easy but I can't figure it out...
I have a file that looks like this:
@SRR057408.1 FW8Y5CK02R652T length=34
AGCAGTGGTATCAACGCAGAGTAAGCAGTGGTAT
+SRR057408.1 FW8Y5CK02R652T length=34
FIIHFF6666?=:88@@@BBD:::?@ABBAAA>8
@SRR057408.2 FW8Y5CK02TBMHV length=52... (1 Reply)
Hi again,
I'm looking for some help with nawk, I can print a line which has a regex match in it from a file using /pattern/ but I'm looking for a way to only print the $tring which contains the pattern, rather than the whole line.
This $tring may be of variable length, may occur at any point... (1 Reply)
I have a file of protein sequences with headers (my source file). Based on a list of IDs (which are included in some of the headers), I'd like to print out only the specified sequences, with only the ID as header.
In other words, I'd like to search source.txt for the terms in IDs.txt, and print... (3 Replies)
Hello,
I need an awk command to print only the lines that match regex on xth field from file.
For example if I use this command
awk -F"|" ' $22 == "20130117090000.*" 'It wont work, I think, because single quotes wont allow the usage of the metacharacter star * . On the other hand I dont know... (2 Replies)
Hi,
I am using the following code to fetch lines that are generated in last 1 hr . Hence, I am using date function to calculate -last 1 hr & the current hr and then somehow use awk (or sed-if someone could guide me better)
with some regex pattern.
dt_1=`date +%h" "%d", "%Y\ %l -d "1 hour... (10 Replies)
Hello.
I have been looking high and low for the solution for this. I seems there should be a simple answer, but alas.
I have a big xml file, and I need to extract certain information from specific items. The information I need can be found between a specific set of tags. let's call them... (2 Replies)
I have a directory of files, I can show the number of lines in each file and order them from lowest to highest with:
wc -l *|sort
15263 Image.txt
16401 reference.txt
40459 richtexteditor.txt
How can I also print the number of unique lines in each file?
15263 1401 Image.txt
16401... (15 Replies)
Discussion started by: spacegoose
15 Replies
LEARN ABOUT DEBIAN
plan9-tail
TAIL(1) General Commands Manual TAIL(1)NAME
tail - deliver the last part of a file
SYNOPSIS
tail [ +-number[lbc][rf] ] [ file ]
tail [ -fr ] [ -n nlines ] [ -c nbytes ] [ file ]
DESCRIPTION
Tail copies the named file to the standard output beginning at a designated place. If no file is named, the standard input is copied.
Copying begins at position +number measured from the beginning, or -number from the end of the input. Number is counted in lines, 1K
blocks or bytes, according to the appended flag or Default is -10l (ten ell).
The further flag causes tail to print lines from the end of the file in reverse order; (follow) causes tail, after printing to the end, to
keep watch and print further data as it appears.
The second syntax is that promulgated by POSIX, where the numbers rather than the options are signed.
EXAMPLES
tail file
Print the last 10 lines of a file.
tail +0f file
Print a file, and continue to watch data accumulate as it grows.
sed 10q file
Print the first 10 lines of a file.
SOURCE
/src/cmd/tail.c
BUGS
Tails relative to the end of the file are treasured up in a buffer, and thus are limited in length.
According to custom, option +number counts lines from 1, and counts blocks and bytes from 0.
Tail is ignorant of UTF.
TAIL(1)