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Full Discussion: awk search pattern
Top Forums Shell Programming and Scripting awk search pattern Post 302454304 by a27wang on Friday 17th of September 2010 02:31:31 PM
Old 09-17-2010
awk search pattern
Hi,

I have a log file which contains lines like below:

Code:
2010-07-19 07:13:19,021 ERROR system ...(text)
2010-07-19 07:22:03,427 ERROR system ...(text)
class com... (text)
2010-07-19 07:23:19,026 ERROR system ...(text)
class com... (text)

each line is a separate line... I am given the a
start time such as : "2010 07 17 07 13 19 "
end time such as: "2010 07 19 20 00 00"
and I have 2 variables which puts them to the format of "2010-07-19 07:13:19" and "2010-07-19 20:00:00

I'm not sure what to put such a search pattern to return the log lines in between (inclusive) the start and end times given, and on the example above, it should return lines afters it as well.

if I put the start time and end time of only the first time log line from above it should be:
Code:
2010-07-19 07:13:19,021 ERROR system ...(text)


if I put the start time and end time of only the second time log line from above it should be:
Code:
2010-07-19 07:22:03,427 ERROR system ...(text)
class com... (text)

if I put the start time and end time of only the third time log line from above it should be:
Code:
2010-07-19 07:23:19,026 ERROR system ...(text)
class com... (text)

or if i just put a start and end time including all it should return everything.. etc

This problem is kind of complicated... I would greatly appreciated if anyone can even lead me in the way of getting it to the correct search outputs.

Thanks

I have the following code which, only looks for the start time for exact matches, and returns.
Code:
awk -vs="$sstart" '$0~"^"s{p=1}!($0~"^"s) && /^2010/{if(p==1){print "\n"}p=o}p' "$f"

$sstart is the format of "2010-07-19 07:13:19", and $F is the file name.
Last edited by Scott; 09-17-2010 at 04:42 PM.. Reason: Please use CODE tags
 

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