---------- Post updated at 12:25 PM ---------- Previous update was at 11:43 AM ----------
So, I've almost got my little script running, but seem stuck again at printing out averages of columns.
What I have in my script is this:
And what I would like to have is:
where 362 is the average in column 7, for that section of the log (see below in my original post).
What I get with my script is this:
Thanks in advance.
Quote:
Originally Posted by euval
Could someone please point me in the right direction with the following?
I have a program that generates logs that contains sections like this:
What I would like to do is produce an awk (or sed) one-liner that would
search between regular expression /IMAGE/ and /ACCEPTED and produce the following output:
Where 81 and 89 are first fields of the first and last number-containing lines respectively. These numbers can be any range between "IMAGE" and "ACCEPTED", but are always consecutive and increment by 1.
Parsing first and last lines that only contain numbers in awk without multiple pipes has got me stuck.
Hi!
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awk '
BEGIN { count=0}
/ZZZZ/ {
list=NR
... (10 Replies)
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its look like this:
271261621371
2727127f
27126|71372.
...
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file.txtone
two
three
3
four
five
5tt
6gfjdfgdf
9
66
six
0
seven
7
eight
546546
gffdg445gfg
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Hello,
i need help with awk.
I have this file:
cat number
DirB port 67 er_enc_out 0 er_bad_os 0
DirB port 71 er_enc_out 56 er_bad_os 0
DirB port 74 er_enc_out 0 er_bad_os 0
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Hi
Does anyone know of an efficient way to index a column of data in file2 to print the coresponding row in file1 which corresponds to the data in file2 AND 30 rows preceding and after the row in file1.
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Hi, I need to print lines which are matching with start pattern "SELECT" and END PATTERN ";" and only select the last "select" statement including the ";" .
I have attached sample input file and the desired input should be as:
INPUT FORMAT:
SELECT
ABCD,
DEFGH,
DFGHJ,
JKLMN,
AXCVB,... (5 Replies)