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Shell Programming and Scripting
To count distinct fields in a row
Post 302453830 by Abhik on Thursday 16th of September 2010 01:36:55 PM
09-16-2010
To count distinct fields in a row
I have . dat file which contains data in a specific format:
0 3 892 921 342
1 3 921 342 543
2 4 817 562 718 765
3 3 819 562 717 761
i need to compare each field in a row with another field of the same column but different row and cont the diffferences between the rows.
For ex: 892!=921 and 921!=342 and 342!=543 hence the (count of the differences between row 0 and row 1) = 3
Similarly i need to count the differences between the fields of row 1 and row 2
row 2 and row 3.. and soo on(not 0-1 , 2-3, 4-5...)
please can anyone body help me with an awk script?
I used NR.. but it is not pointing back to an already visited row
0 3 892 921 342
1 3 921 342 543
2 4 817 562 718 765
3 3 819 562 717 761
i need to compare each field in a row with another field of the same column but different row and cont the diffferences between the rows.
For ex: 892!=921 and 921!=342 and 342!=543 hence the (count of the differences between row 0 and row 1) = 3
Similarly i need to count the differences between the fields of row 1 and row 2
row 2 and row 3.. and soo on(not 0-1 , 2-3, 4-5...)
please can anyone body help me with an awk script?
I used NR.. but it is not pointing back to an already visited row
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