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Top Forums Shell Programming and Scripting How to calculate time difference between start and end time of a process! Post 302450401 by frans on Thursday 2nd of September 2010 01:05:47 PM
Old 09-02-2010
With GNU date

Code:
#!/bin/bash
StartDate="08/05/10 12:55"
EndDate="08/09/10 06:50"
HRS=$((($(date -d "$EndDate" +%s)-$(date -d "$StartDate" +%s))/3600))
WHRS=$HRS
for (( D=1; D<$((HRS/24+1)); D++ ))
do
   [ $(date -d "$StartDate $D days" +%u) -ge 6 ] && ((WHRS-=24))
done
echo "Working time elapsed='$WHRS'"

As a function
Code:
#!/bin/bash
Elapsed()	{
   HRS=$((($(date -d "$2" +%s)-$(date -d "$1" +%s))/3600))
   WHRS=$HRS
   for (( D=1; D<$((HRS/24+1)); D++ ))
   do
      [ $(date -d "$1 $D days" +%u) -ge 6 ] && ((WHRS-=24))
   done
   echo $WHRS
}
StartDate="08/05/10 12:55"
EndDate="08/09/10 06:50"
echo "Working time elapsed='$(Elapsed "$StartDate" "$EndDate")'"

 

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DATE_PARSE_FROM_FORMAT(3)						 1						 DATE_PARSE_FROM_FORMAT(3)

date_parse_from_format - Get info about given date formatted according to the specified format

SYNOPSIS
array date_parse_from_format (string $format, string $date) DESCRIPTION
Returns associative array with detailed info about given date. PARAMETERS
o $format - Format accepted by DateTime.createFromFormat(3). o $date - String representing the date. RETURN VALUES
Returns associative array with detailed info about given date. EXAMPLES
Example #1 date_parse_from_format(3) example <?php $date = "6.1.2009 13:00+01:00"; print_r(date_parse_from_format("j.n.Y H:iP", $date)); ?> The above example will output: Array ( [year] => 2009 [month] => 1 [day] => 6 [hour] => 13 [minute] => 0 [second] => 0 [fraction] => [warning_count] => 0 [warnings] => Array ( ) [error_count] => 0 [errors] => Array ( ) [is_localtime] => 1 [zone_type] => 1 [zone] => -60 [is_dst] => ) SEE ALSO
DateTime.createFromFormat(3), checkdate(3). PHP Documentation Group DATE_PARSE_FROM_FORMAT(3)
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