Sponsored Content
Top Forums Shell Programming and Scripting How to remove last character in a string read from file Post 302450398 by Scott on Thursday 2nd of September 2010 12:59:25 PM
Old 09-02-2010
Hi.

You could probably do that in one step.

i.e.
Code:
sed -e 's/[, ]*$//g'

This User Gave Thanks to Scott For This Post:
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

read and assign each character from the string to a variable

How... can I read input by a user character by cahracter. And assign each character from the string to a variable? Any help would be greatly appreciated! Thank you! (1 Reply)
Discussion started by: Tek-E
1 Replies

2. Shell Programming and Scripting

read in a file character by character - replace any unknown ASCII characters with spa

Can someone help me to write a script / command to read in a file, character by character, replace any unknown ASCII characters with space. then write out the file to a new filename/ Thanks! (1 Reply)
Discussion started by: raghav525
1 Replies

3. Shell Programming and Scripting

bash while read how to remove \n character

Hi, I've made a script to grep a file for i in `cat filename.txt` do strings ./binfile | grep "$i" 2>&1 > /dev/null done this works fine as long as in filename.txt i don't have any entries with spaces. But in my case i want to grep something with spaces like "lala tata" and... (3 Replies)
Discussion started by: papasj
3 Replies

4. Shell Programming and Scripting

shell script to remove the last character(.) of a string

hi I have a list of words in a text file. these words are appended by "." at their end. They look something like this. word1. word2. word3. word4. word5. I need to remove the last character "." from all the words. The output must look something like this. word1 word2 word3... (7 Replies)
Discussion started by: ss3944
7 Replies

5. Shell Programming and Scripting

How to remove the first character on a string in a variable

Hi all, Does anyone know how to code in ksh that will remove the first character in a string variable and replace that variable without the first character? Example: var1=ktest1 will become var1=test1 var2=rtest2 will become var2=test2 Need help please. (10 Replies)
Discussion started by: ryukishin_17
10 Replies

6. Shell Programming and Scripting

read the text file and print the content character by character..

hello all i request you to give the solution for the following problem.. I want read the text file.and print the contents character by character..like if the text file contains google means..i want to print g go goo goog googl google like this Using unix Shell scripting... without using... (1 Reply)
Discussion started by: samupnl
1 Replies

7. Shell Programming and Scripting

remove the first and last character of a string

How can i remove the first and last character of strings like below: "^^^613*" "admt130" "^^^613*" "123456" "adg8484" "DQitYV09dh1C" Means i wanna remove the quotes(""). Please help (17 Replies)
Discussion started by: proactiveaditya
17 Replies

8. Shell Programming and Scripting

Bash: How to remove the last character of a string?

In bash, how can one remove the last character of a string? In perl, the chop function would remove the last character. However, I do not know how to do the same job in bash. Many thanks in advance. (12 Replies)
Discussion started by: LessNux
12 Replies

9. Shell Programming and Scripting

gawk to remove last character in a line or string

I am outputting a line like this print $2 "/" $4The last character though is a ":" and I want to remove it. Is there any neat way to remove it? Or am I forced to do something like this: print $2 "/" substr($4, 1, length($4) - 1)Thanks. (6 Replies)
Discussion started by: benalt
6 Replies

10. UNIX for Beginners Questions & Answers

Remove string between number and character

hello ! I have to remove string between a number and set of characters. For example, 35818 -stress - - -stress - - - - - - DB-3754 44412 caul kid notify DB-3747 54432 roberto -, notify DB-3725 55522 aws _ _int _ _classified 2_a _a 2_m _m 2_classified 2_search... (7 Replies)
Discussion started by: ManoharMa
7 Replies
regexpr(3GEN)					     String Pattern-Matching Library Functions					     regexpr(3GEN)

NAME
regexpr, compile, step, advance - regular expression compile and match routines SYNOPSIS
cc [flag...] [file...] -lgen [library...] #include <regexpr.h> char *compile(char *instring, char *expbuf, const char *endbuf); int step(const char *string, const char *expbuf); int advance(const char *string, const char *expbuf); extern char *loc1, loc2, locs; extern int nbra, regerrno, reglength; extern char *braslist[], *braelist[]; DESCRIPTION
These routines are used to compile regular expressions and match the compiled expressions against lines. The regular expressions compiled are in the form used by ed(1). The parameter instring is a null-terminated string representing the regular expression. The parameter expbuf points to the place where the compiled regular expression is to be placed. If expbuf is NULL, compile() uses mal- loc(3C) to allocate the space for the compiled regular expression. If an error occurs, this space is freed. It is the user's responsibil- ity to free unneeded space after the compiled regular expression is no longer needed. The parameter endbuf is one more than the highest address where the compiled regular expression may be placed. This argument is ignored if expbuf is NULL. If the compiled expression cannot fit in (endbuf-expbuf) bytes, compile() returns NULL and regerrno (see below) is set to 50. The parameter string is a pointer to a string of characters to be checked for a match. This string should be null-terminated. The parameter expbuf is the compiled regular expression obtained by a call of the function compile(). The function step() returns non-zero if the given string matches the regular expression, and zero if the expressions do not match. If there is a match, two external character pointers are set as a side effect to the call to step(). The variables set in step() are loc1 and loc2. loc1 is a pointer to the first character that matched the regular expression. The variable loc2 points to the character after the last character that matches the regular expression. Thus if the regular expression matches the entire line, loc1 points to the first char- acter of string and loc2 points to the null at the end of string. The purpose of step() is to step through the string argument until a match is found or until the end of string is reached. If the regular expression begins with ^, step() tries to match the regular expression at the beginning of the string only. The advance() function is similar to step(); but, it only sets the variable loc2 and always restricts matches to the beginning of the string. If one is looking for successive matches in the same string of characters, locs should be set equal to loc2, and step() should be called with string equal to loc2. locs is used by commands like ed and sed so that global substitutions like s/y*//g do not loop forever, and is NULL by default. The external variable nbra is used to determine the number of subexpressions in the compiled regular expression. braslist and braelist are arrays of character pointers that point to the start and end of the nbra subexpressions in the matched string. For example, after calling step() or advance() with string sabcdefg and regular expression (abcdef), braslist[0] will point at a and braelist[0] will point at g. These arrays are used by commands like ed and sed for substitute replacement patterns that contain the notation for subexpressions. Note that it is not necessary to use the external variables regerrno, nbra, loc1, loc2 locs, braelist, and braslist if one is only checking whether or not a string matches a regular expression. EXAMPLES
Example 1: The following is similar to the regular expression code from grep: #include<regexpr.h> . . . if(compile(*argv, (char *)0, (char *)0) == (char *)0) regerr(regerrno); . . . if (step(linebuf, expbuf)) succeed(); RETURN VALUES
If compile() succeeds, it returns a non-NULL pointer whose value depends on expbuf. If expbuf is non-NULL, compile() returns a pointer to the byte after the last byte in the compiled regular expression. The length of the compiled regular expression is stored in reglength. Otherwise, compile() returns a pointer to the space allocated by malloc(3C). The functions step() and advance() return non-zero if the given string matches the regular expression, and zero if the expressions do not match. ERRORS
If an error is detected when compiling the regular expression, a NULL pointer is returned from compile() and regerrno is set to one of the non-zero error numbers indicated below: ERROR MEANING 11 Range endpoint too large. 16 Bad Number. 25 "digit" out or range. 36 Illegal or missing delimiter. 41 No remembered string search. 42 (~) imbalance. 43 Too many (. 44 More than 2 numbers given in [~}. 45 } expected after . 46 First number exceeds second in {~}. 49 [] imbalance. 50 Regular expression overflow. ATTRIBUTES
See attributes(5) for descriptions of the following attributes: +-----------------------------+-----------------------------+ | ATTRIBUTE TYPE | ATTRIBUTE VALUE | +-----------------------------+-----------------------------+ |MT-Level |MT-Safe | +-----------------------------+-----------------------------+ SEE ALSO
ed(1), grep(1), sed(1), malloc(3C), attributes(5), regexp(5) NOTES
When compiling multi-threaded applications, the _REENTRANT flag must be defined on the compile line. This flag should only be used in multi-threaded applications. SunOS 5.10 29 Dec 1996 regexpr(3GEN)
All times are GMT -4. The time now is 05:01 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy