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Top Forums Shell Programming and Scripting How to pass shell variables to awk's pattern? Post 302450396 by kchinnam on Thursday 2nd of September 2010 12:54:15 PM
Old 09-02-2010
That works,, why this version of syntax does not use !!?

Quote:
'$3 ~ /var1/'
instead it uses
Quote:
'$3 ~ var1'
When I replace var1 with its value without // wrapping it does not work..
 

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The mysqli_stmt class

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