08-29-2010
10 More Discussions You Might Find Interesting
1. UNIX for Dummies Questions & Answers
Hello,
Please can someone help me in getitng last 7 days from the current date?
for eg:
input /default : today (10/18/2004)
required output:
10/17/2004
10/16/2004
10/15/2004
10/14/2004
10/13/2004
... (6 Replies)
Discussion started by: Anamika
6 Replies
2. Shell Programming and Scripting
Looking for some help on capturing the number of days in a month to set as a loop counter. Any ideas, please let me know. (3 Replies)
Discussion started by: flounder
3 Replies
3. Shell Programming and Scripting
does any one have any ideas how i would go about calculating the number of days left in the month from a bash script ?. I want to do some operations on a csv file according to the result (8 Replies)
Discussion started by: dunryc
8 Replies
4. Shell Programming and Scripting
I am writing a script that requires the number of days in any given month.
In the shell, I can use the command:
cal `date +%m` `date +%Y`| grep -v '' | wc -w
to give me the number of days in the month, but when I assign it to a variable:
VAR=`cal `date +%m` `date +%Y`| grep -v '' | wc... (3 Replies)
Discussion started by: skaptakalian
3 Replies
5. Shell Programming and Scripting
Hi all. I am scripting in a POSIX shell on HPUX.
I am running a script that needs to determine the number of days in a month.
I found this on the forum and it works great:
X=`cal $(date +%m) $(date +%Y) | grep -v '' | wc -w`
The issue is that I am running the script on the 7th day of... (11 Replies)
Discussion started by: lyoncc
11 Replies
6. Programming
Hi,
I have an issue in date processing, the issue is I have a month as an int ( 1 - 12 ), the weekday as int ( 0 - 6 , 0 = Sunday), and the week day in month as int ( 0 - 5, 5 = last ex: first sunday, last monday, third tuesday ... ), now from those three parameters is there a possible way to... (2 Replies)
Discussion started by: modn3
2 Replies
7. Shell Programming and Scripting
hi all
searched google and here, cant find and am begining to suspect there is no options for this.
shell = born
with either the date or cal command I need to display the number of days in current month. can anyone point me in the right direction? (10 Replies)
Discussion started by: rontopia
10 Replies
8. Shell Programming and Scripting
Hi Guru's,
I am working on a shell script from past a month and unable to get rid of automating while working with dates,here's what i have.
inital_date=11012011
final_date=11302011
expected_output= has to be in below format PFB
11012011
11022011
11032011
*
*
*
11102011
*
*... (9 Replies)
Discussion started by: Gaurav198
9 Replies
9. Shell Programming and Scripting
I have a homework assignment:
----------------------------------------
"Display" the number of days in the current month. For example:
September 1996 has 30 days
----------------------------------------
I am trying to just display the head of cal to start the sentence.
eg. cal | head
... (1 Reply)
Discussion started by: eaafuddy
1 Replies
10. Shell Programming and Scripting
Hi,
I have a script that accepts an input date from the user in yyyy-mm-dd format.
I need to get the mm-dd part and convert it to month name.
example:
2011-11-15
I want that to become "Nov 15"
I don't have the GNU date, I am using an AIX os.
Thanks. (1 Reply)
Discussion started by: erin00
1 Replies
CAL(1) User Commands CAL(1)
NAME
cal - display a calendar
SYNOPSIS
cal [options] [[[day] month] year]
DESCRIPTION
cal displays a simple calendar. If no arguments are specified, the current month is displayed.
OPTIONS
-1, --one
Display single month output. (This is the default.)
-3, --three
Display prev/current/next month output.
-s, --sunday
Display Sunday as the first day of the week.
-m, --monday
Display Monday as the first day of the week.
-j, --julian
Display Julian dates (days one-based, numbered from January 1).
-y, --year
Display a calendar for the current year.
-V, --version
Display version information and exit.
-h, --help
Display help screen and exit.
PARAMETERS
A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: cal 89 will not display a calendar
for 1989.
Two parameters denote the month (1 - 12) and year.
Three parameters denote the day (1-31), month and year, and the day will be highlighted if the calendar is displayed on a terminal. If no
parameters are specified, the current month's calendar is displayed.
A year starts on Jan 1. The first day of the week is determined by the locale.
The Gregorian Reformation is assumed to have occurred in 1752 on the 3rd of September. By this time, most countries had recognized the ref-
ormation (although a few did not recognize it until the early 1900's). Ten days following that date were eliminated by the reformation, so
the calendar for that month is a bit unusual.
HISTORY
A cal command appeared in Version 6 AT&T UNIX.
AVAILABILITY
The cal command is part of the util-linux package and is available from ftp://ftp.kernel.org/pub/linux/utils/util-linux/.
util-linux June 2011 CAL(1)