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Top Forums Shell Programming and Scripting Need Awk command to get part of string based on delimeter Post 302449143 by shanneykar on Saturday 28th of August 2010 05:54:33 PM
Old 08-28-2010
It's Working... but need to research ur command dude. Smilie Thanks a bunch.

---------- Post updated at 04:16 PM ---------- Previous update was at 04:02 PM ----------

Sorry , I edited th eline to make it simple. My actual input

Input : "06:28:45 28.08.2010|SCHEDULE: Started program POSG1[(0600 08/27/10),(0AAAAAAAAAAAOG66)].PLK110 (#J2325) has completed successfully"

Output :07:08:43 28.08.2010 08/28/10

The awk command given is fetching "07:08:43 28.08.2010 (#J2325"

Please help. Sorry about last time[COLOR="#738fbf"]

Last edited by Scott; 08-28-2010 at 07:01 PM.. Reason: Removed "bump"
 

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IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). Free Software Foundation Nov 3 1999 IGAWK(1)
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