Hi
I have a sed command
sed -e "s/sub_date/=$(date +"%d/%m/%Y")/" sub_create_tmp
I want to substitute with the current date in dd/mm/yyyy format .
But the result is an error " cannot parse " .
Pls help .
sars (2 Replies)
I have a file with some date columns in MM/DD/YYYY format:
SMPBR|DUP-DO NOT USE|NEW YORK||16105|BA5270715|6/6/2007 |MWERNER|109||||JOHN||SMITH|MD|72211118||||||74559|21 WILMINGTON RD||D|11/6/2003|SL# MD CONTACT-LIZ RICHARDS|||0|Y|N||1411458|
And I want to convert the date format to:
... (5 Replies)
Frens,
I have a logfile which has got manier things in it and somewer in that file i have a date in mm/dd/yyyy hh:mm format....
I just need to get the date and time nothing else....
i have searched in this forum for it but got only date in mm-dd-yyyy format..
but i need to search for... (10 Replies)
(Attention: Green PHP newbie !)
I have an online inquiry form, delivering a date in the form yyyy/mm/dd to my feedback form. If the content passes several checks, the form sends an e-mail to me. All works fine. I just would like to receive the date in the form dd/mm/yyyy. I tried with some code,... (6 Replies)
could you please help be on the below code ..
Requirement is when i pass the parameter(for below 2) i should get current time -2 hours in the format :wall:..
cur_dt=`$ICEBIN/sqsh -S$DSQUERY -U $BATCHID -P $PASSWD -h -C"select getdate()" | sed '2d'`
pr_dt="`$ICEBIN/sqsh -S$DSQUERY -U $BATCHID... (2 Replies)
Hi,
I am having one log files. contains som data according to date. And it is going to append .Eg:abc.log contains below data
2011-10-19 abjhgj
2011-10-19 gjhgjgj
2011-10-20 hhhjh
2011-10-20 hhhhjj
2011-10-21 gg
.
.
.
2011-11-24 yyy
from log files i want catch only... (2 Replies)
How can I convert any user inputted date into yyyy/mm/dd ?
For example user can input date one of the following 20120121 , 2012-01-21 ,01/21/2012,01/21/2012 etc
But I need to convert any of the date entered by user into yyyy/mm/dd (2012/01/2012). Any suggestion. Thanks in advance
this is... (1 Reply)
I am changing epoch times to dates. I was able to do the following:
echo "$varx" | gawk '{print strftime("%c", $0)}'
Mon Dec 31 16:26:40 2012
This changes the epoch date (which is what varx is) into localtime.
However, my problem is that I only want 12/31/2012 and not the Mon Dec 31... (2 Replies)
I need the date format in YYYY.MM format and I am able to get current month date as well as previous month date with below command
PM=`date +'%Y.%m' -d 'last month'`
CM=`date +'%Y.%m' -d 'now'`
but I need to get YYYY.MM date format for previous 12 months so could you please help me how I get... (2 Replies)
I am getting output of YYYY-MM-DD and want to change this to DD/MM/YYYY.
When am running the query in 'Todd' to_date(column_name,'DD/MM/YYYY') am getting the required o/p of DD/MM/YYYY, But when am executing the same query(Netezza) in linux server(bash) am getting the output of YYYY-MM-DD
file... (3 Replies)
Discussion started by: Roozo
3 Replies
LEARN ABOUT CENTOS
xzcmp
XZDIFF(1) XZ Utils XZDIFF(1)NAME
xzcmp, xzdiff, lzcmp, lzdiff - compare compressed files
SYNOPSIS
xzcmp [cmp_options] file1 [file2]
xzdiff [diff_options] file1 [file2]
lzcmp [cmp_options] file1 [file2]
lzdiff [diff_options] file1 [file2]
DESCRIPTION
xzcmp and xzdiff invoke cmp(1) or diff(1) on files compressed with xz(1), lzma(1), gzip(1), bzip2(1), or lzop(1). All options specified
are passed directly to cmp(1) or diff(1). If only one file is specified, then the files compared are file1 (which must have a suffix of a
supported compression format) and file1 from which the compression format suffix has been stripped. If two files are specified, then they
are uncompressed if necessary and fed to cmp(1) or diff(1). The exit status from cmp(1) or diff(1) is preserved.
The names lzcmp and lzdiff are provided for backward compatibility with LZMA Utils.
SEE ALSO cmp(1), diff(1), xz(1), gzip(1), bzip2(1), lzop(1), zdiff(1)BUGS
Messages from the cmp(1) or diff(1) programs refer to temporary filenames instead of those specified.
Tukaani 2011-03-19 XZDIFF(1)