08-20-2010
10 More Discussions You Might Find Interesting
1. UNIX for Dummies Questions & Answers
I would like to know how I could get a yesterday date in yyyymmdd e.g. today is 20011109, and I would like to get 20011108. Thank you!:confused: (2 Replies)
Discussion started by: hk_newbie
2 Replies
2. HP-UX
How can i get the yesterday's date in YYYYMMDD format??? (4 Replies)
Discussion started by: prasadsr
4 Replies
3. Shell Programming and Scripting
how can i get yesterday in yyyymmdd format? :confused: (13 Replies)
Discussion started by: aaron_fong
13 Replies
4. UNIX for Dummies Questions & Answers
I have a file with some date columns in MM/DD/YYYY format:
SMPBR|DUP-DO NOT USE|NEW YORK||16105|BA5270715|6/6/2007 |MWERNER|109||||JOHN||SMITH|MD|72211118||||||74559|21 WILMINGTON RD||D|11/6/2003|SL# MD CONTACT-LIZ RICHARDS|||0|Y|N||1411458|
And I want to convert the date format to:
... (5 Replies)
Discussion started by: ChicagoBlues
5 Replies
5. Shell Programming and Scripting
Hi ,
i have doubt in bash shell script..
for example my file name is sampledate.sh
given command = ./sampledate.sh -d 20100303 -f karthi
how to find the next day from 20100303 (YYYYMMDD format)
After getting the next day ,changed date and -f argument value will be sent to one java class.
... (13 Replies)
Discussion started by: karthinvk
13 Replies
6. Shell Programming and Scripting
How do I change the date format from mmddyyyy to yyyymmdd in PERL.
Can any one help me please. (3 Replies)
Discussion started by: thankful123
3 Replies
7. Solaris
Hi Experts,
How to get date 5 days after current date in YYYYMMDD format?
How do we compare date in YYYYMMDD format?
Thanks (1 Reply)
Discussion started by: needyourhelp10
1 Replies
8. Shell Programming and Scripting
My requirement is:- there will be files at a location each day with the date format DDMMYYYY.
Novawise_Activity_Call_Notes_04022013.txt
Novawise_Activity_Inbound_04022013.txt
Novawise_Activity_Inbound_05022013.txt
Novawise_Activity_Call_Notes_05022013.txt... (8 Replies)
Discussion started by: djrulz123
8 Replies
9. UNIX for Dummies Questions & Answers
I have this filename "RBD_EXTRACT_a3468_d20131118.tar.gz" and I would like print out the "yyyymmdd" only. I use this command below, but if different command like cut or print....etc. Thanks
ls RBD_EXTRACT* | sed 's/.*\(........\).tar.gz$/\1/' > test.txt (9 Replies)
Discussion started by: dotran
9 Replies
10. Shell Programming and Scripting
I would like to convert YYYYMMDD to MJD format
for eg 20041223 converted to 53362 in MJD format i got logic from javascript to covert it to MJD which is long enough
function YMDtoMJD (year, month, day)
{
var year;
var monthi
var day;
var yr = Math.floor (year);
... (1 Reply)
Discussion started by: mandalmanas24
1 Replies
LEARN ABOUT DEBIAN
zip_set_archive_comment
ZIP_SET_ARCHIVE_COMMENT(3) Library Functions Manual ZIP_SET_ARCHIVE_COMMENT(3)
NAME
zip_set_archive_comment - set zip archive comment
LIBRARY
libzip (-lzip)
SYNOPSIS
#include <zip.h>
int zip_set_archive_comment(struct zip *archive); "const char *comment" "int len"
DESCRIPTION
The zip_set_archive_comment function sets the comment for the entire zip archive. If comment is NULL and len is 0, the archive comment
will be removed.
RETURN VALUES
Upon successful completion 0 is returned. Otherwise, -1 is returned and the error information in archive is set to indicate the error.
ERRORS
zip_set_archive_comment fails if:
[ZIP_ER_INVAL]
len is less than 0 or longer than the maximum comment length in a zip file (65535).
[ZIP_ER_MEMORY]
Required memory could not be allocated.
SEE ALSO
libzip(3), zip_get_archive_comment(3), zip_get_file_comment(3), zip_set_file_comment(3)
AUTHORS
Dieter Baron <dillo@giga.or.at> and Thomas Klausner <tk@giga.or.at>
NiH October 26, 2007 ZIP_SET_ARCHIVE_COMMENT(3)