Hi ALL
I have small script that find 777 dir now i want to count these directories,Keep in mind there are many directories.
This IS my code below.
#!/bin/bash
check=/var/www/html
find $check -type d -perm 777 | while read DIR
do
... (2 Replies)
Hello,
I am looking for a way to get the TOTAL COUNT of the files present in all directories(sub directories) under the root directory..The files can be of any type viz. txt, doc, html, wav, jpeg etc. If it has an extension, it has to be counted..
I want to run the script from the root directory.... (6 Replies)
Hey,
I'm very new to AWK and am trying to write a script that counts the number of files in all subdirectories. So, basically, my root has many subdirectories, and each subdirectory has many files.
How can I get the total count? I haven't been able to figure out how to loop through the... (1 Reply)
Hi,
I have a requirement to find out the count of files in directories. I can do this very well by goind to each directory and then ls -lrt | wc -l. But I need to do it for hundreds of directories/sub-directories.
I tried with this -
for i in `ls -F | grep '/$'`; do `echo "$i"`| ls -lrt... (2 Replies)
Hi
I have a jfs2 filesystem named /software in my aix 5.3 box.
Please note that there are a lot of subdirectories under /software?
I need to know the count of how many total files and directories are present under that mount point /software ?
For example if by some commands we find that there... (3 Replies)
Hi All!
I would like to have a script that will count the number of files at the top of the hour of soome directories and mail the results to me.
I was thinking on :
a=`/directory/subdirectory/ | wc -l`
echo "/directory/subdirectory :$a"
b=`/another_dir/subdir/ | wc -l`
echo... (12 Replies)
I'm trying to make a script that will list all directories under a selection as well as the number of files in each.
I cannot get it to work under a symbolic link.
The file structure is:
XXX_20131127_001
dir01 (sym link)
2404x912
file.0000.xxx to
... (10 Replies)
Hi All,
Everyday we will receive 33 files in our source directory(/prd/pk) with the current date. Once our jobs are completed all the 33 files immediately will be moved to backup folder (/prd/pk/backup).
Now, I need to check between source file directory (/prd/pdk) and backup file directory... (3 Replies)
I have searched this quite a long time but couldn't find the right method for me to use. I need to assign read write permission to the user for specific directories and it's sub directories and files. I do not want to use ACL. This is for Solaris. Please help. (1 Reply)
Discussion started by: blinkingdan
1 Replies
LEARN ABOUT POSIX
zgrep
ZGREP(1) General Commands Manual ZGREP(1)NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)ZGREP(1)