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Top Forums Shell Programming and Scripting Get PID of a process into a variable Post 302444370 by Scott on Wednesday 11th of August 2010 05:20:39 PM
Old 08-11-2010
Quote:
Originally Posted by bartus11
I think it won't work until you put it like that:
Code:
var=`echo ${!}`
echo $var

Couse without "{}" it tries to use ! as bash command. Anyway your second solution is much better Smilie
Hmm. Interesting, but it seems to work fine:

Code:
$ bash
$ cat Slp
sleep 3 &
var=`echo $!`
echo var is $var 
ps -ef | grep [s]leep


$ ./Slp
var is 77811
  503 77811 77810   0   0:00.00 ttys001    0:00.00 sleep 3

(but, yes, the command sub isn't neccessary anyway)
 

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SETSID(2)						     Linux Programmer's Manual							 SETSID(2)

NAME
setsid - creates a session and sets the process group ID SYNOPSIS
#include <unistd.h> pid_t setsid(void); DESCRIPTION
setsid() creates a new session if the calling process is not a process group leader. The calling process is the leader of the new session, the process group leader of the new process group, and has no controlling tty. The process group ID and session ID of the calling process are set to the PID of the calling process. The calling process will be the only process in this new process group and in this new session. RETURN VALUE
The session ID of the calling process. ERRORS
On error, -1 will be returned. The only error which can happen is EPERM. It is returned when the process group ID of any process equals the PID of the calling process. Thus, in particular, setsid fails if the calling process is already a process group leader. NOTES
A process group leader is a process with process group ID equal to its PID. In order to be sure that setsid will succeed, fork and exit, and have the child do setsid(). CONFORMING TO
POSIX, SVr4. SEE ALSO
setpgid(2), setpgrp(2) Linux 1.0.0 1994-08-27 SETSID(2)
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