Hi,
I need a shell script which should find the latest date in the field of file and print that line only. For eg.,
I have a file /date.log
Name Date Status
IBM 06/06/07 close
DELL 07/27/07 open
DELL 06/07/07 open
: : :
From... (1 Reply)
suppose
fileA
kanika123ABC 1222222222222222
raciat5678ty 1221123333331121
jessica78ulllo 2233243223333333
so output shud be print only first 10 characters in series and rest remain same
kanika123A 1222222222222222
raciat5678 1221123333331121
jessica78u ... (1 Reply)
Hi guys. i have the following script:
1 #!/bin/bash
2 linkcount=$(grep "/portal" tickets | wc -l)
3 grep "/portal" tickets > links
4 for i in $(seq 1 $linkcount); do
5 echo "BLYAT"
6 let link$i=$(sed -n "$i"p links)
7 echo $
8 done
the problem is, that "let" can`t... (1 Reply)
Hello friends,
I am looking for a script or method that can display all the dates between any 2 given dates.
Input:
Date 1
290109
Date 2
010209
Output:
300109
310109
Please help me. Thanks. :):confused: (2 Replies)
can anyone please suggest me on ideas to write a script which has to go back to 100 days from 'current date' and print the date of each day starting from 100th day to current day. (korn shell please)
Thanks
Pavan (5 Replies)
Hi all. Im trying to use a sequence in a while loop like this below. I need it for navigating a year, month, day folder structure where a user can input the start date and have it go to the desired end date. The script will grab a certain file on each day then move onto the next. Ive got all that... (3 Replies)
I usually just browse the forum/google for answers, however I've been stuck on a problem for a number of hours now and I've decided to join up and actually ask I've searched the forum ad naseum in an attempt to find answer to my query, however so far I have been unsuccessful.
I'm no expert... (3 Replies)
Greetings,
Using linux based OS and KSH.
I m trying to make a simple script to parse some logs to show a count per hour on a specific alarm starting from midnight to the current hour.
So I format my "HOUR" variable to show the current time and so I can use it in the following bit of code.... (6 Replies)
I am processing RNA-seq data files that have been aligned using RUM. One of the output files is a *.sam that includes:
Unique alignments
Non-unique alignments
original read files
I want to extract only the unique alignments by pulling out alignments that have "IH:i:1" (indicates this read... (2 Replies)
Hi! I'm trying to do this:
1 -
2 -
3 -
4 -
5 -
I'm using seq for this:
seq 1 20 > filename.txt
How do I get the "-"? I've tried -f per man but can't get anything to work. Also, is there an easier or better way than using sequence? Thanks! (6 Replies)
Discussion started by: TonyBe
6 Replies
LEARN ABOUT CENTOS
cal
CAL(1) User Commands CAL(1)NAME
cal - display a calendar
SYNOPSIS
cal [options] [[[day] month] year]
DESCRIPTION
cal displays a simple calendar. If no arguments are specified, the current month is displayed.
OPTIONS -1, --one
Display single month output. (This is the default.)
-3, --three
Display prev/current/next month output.
-s, --sunday
Display Sunday as the first day of the week.
-m, --monday
Display Monday as the first day of the week.
-j, --julian
Display Julian dates (days one-based, numbered from January 1).
-y, --year
Display a calendar for the current year.
-V, --version
Display version information and exit.
-h, --help
Display help screen and exit.
PARAMETERS
A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: cal 89 will not display a calendar
for 1989.
Two parameters denote the month (1 - 12) and year.
Three parameters denote the day (1-31), month and year, and the day will be highlighted if the calendar is displayed on a terminal. If no
parameters are specified, the current month's calendar is displayed.
A year starts on Jan 1. The first day of the week is determined by the locale.
The Gregorian Reformation is assumed to have occurred in 1752 on the 3rd of September. By this time, most countries had recognized the ref-
ormation (although a few did not recognize it until the early 1900's). Ten days following that date were eliminated by the reformation, so
the calendar for that month is a bit unusual.
HISTORY
A cal command appeared in Version 6 AT&T UNIX.
AVAILABILITY
The cal command is part of the util-linux package and is available from ftp://ftp.kernel.org/pub/linux/utils/util-linux/.
util-linux June 2011 CAL(1)