Problem in extraction when space is a field delimiter
I have more than 1000 files to parse. Each file contains few lines (number of lines varies) followed by a header line having all column's name (SPOT, NAME etc) and then values for those columns.
**Example File:
. . . . . .
. . . . . .
Problems:
1) I need to remove all lines before the header line (for each file).
2) I need to extract 2 columns, let say 2nd (NAME) & 5th column (CHDN_MED). Since there is no values for 2nd & 4th rows for 5th column, it should give a blank space for each in output file. But its giving 6.3 and 6.7 respectively from the 6th column (I am tring with AWK).
The desired output file is :
**the actual files are with .xls extension and each file has more than 50 columns and 9,000 rows.
Please advise
Thanks
Last edited by Scott; 08-09-2010 at 10:03 AM..
Reason: Please use code tags
Hi Experts,
I need to extract some set of strings one be one using delimiter.
Example:
shellscript.sh|unix.sh|script_file.sh
i need to extract this shellscript.sh,unix.sh,script_file.sh
separately.
I tried but couldn't get. Please help me..
Thanks & Regards :),
Kanda (3 Replies)
The typical line of the input file is as follows,
123|abcde|"xyz|mn"|ghelosa|3455hello|
The delimiter is |. I need to change it to another delimiter, say ~. For the above line, the output should be:
123~abcde~xyz|mn~ghelosa~3455hello~
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I am trying to extract 'postmaster' from the following string:
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using the following command:
cat /usr/share/assp/assp.cfg | grep ^PenaltyError:= | cut -d '@' -f1 | cut -f8
but it returns:
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Hello,
Is there a direct command to check if the delimiter in your file is a tab or a space? And how can they be converted from one to another.
Thanks,
G (4 Replies)
I have a file with three fields and field delimiter '|' like:
abc|12:13:45|123
xyz|12:87:32|
qwe|54:21:09
In the file the 1st line has proper data -> abc|12:13:45|123
,the 2nd line doesnt has data for the 3rd field which is okay
, the 3rd line doesnt has data for the 3rd field as well the... (5 Replies)
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... (18 Replies)
not sure if i'm doing this right i'm new tho this but i'm trying to use a space as a delimiter with the cut command
my code is
size=$( du -k -S -s /home/cmik | cut -d' ' -f1 )
i've also tried -f2 and switching the -d and -f around if that does anything (3 Replies)
We have a csv file as mentioned below and the requirement is to change the date format in file as mentioned below.
Current file (file.csv)
----------------------
empname,date_of_join,dept,date_of_resignation
ram,08/09/2015,sales,21/06/2016
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... (6 Replies)
Discussion started by: gopal.biswal
6 Replies
LEARN ABOUT MOJAVE
colrm
COLRM(1) BSD General Commands Manual COLRM(1)NAME
colrm -- remove columns from a file
SYNOPSIS
colrm [start [stop]]
DESCRIPTION
The colrm utility removes selected columns from the lines of a file. A column is defined as a single character in a line. Input is read
from the standard input. Output is written to the standard output.
If only the start column is specified, columns numbered less than the start column will be written. If both start and stop columns are spec-
ified, columns numbered less than the start column or greater than the stop column will be written. Column numbering starts with one, not
zero.
Tab characters increment the column count to the next multiple of eight. Backspace characters decrement the column count by one.
ENVIRONMENT
The LANG, LC_ALL and LC_CTYPE environment variables affect the execution of colrm as described in environ(7).
EXIT STATUS
The colrm utility exits 0 on success, and >0 if an error occurs.
SEE ALSO awk(1), column(1), cut(1), paste(1)HISTORY
The colrm command appeared in 3.0BSD.
BSD August 4, 2004 BSD