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Top Forums Shell Programming and Scripting Need some help with a regex if loop problem Post 302443430 by alister on Monday 9th of August 2010 12:03:17 AM
Old 08-09-2010
Quote:
Originally Posted by linuxkid
Need some help with a regex if loop problem.
File1:
Code:
2323
3232
4230
3230
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4343
233
32320

I want to print "Zero" if the number ends with a zero, but print "number" if it does not!
Code:
#!/bin/bash
/usr/bin/nawk '{
if ($1 ==/[0-9]+0\b/){
 print "Zero"}
else{
 print "number"}
}' File1

this code just prints out "Number" for each line! Help!
In addition to the operator error pointed out by durden_tyler, \b in an awk regular expression is an escape sequence which matches the backspace character (unlike in perl where it refers to a word boundary).
 

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RE_COMP(3)						     Linux Programmer's Manual							RE_COMP(3)

NAME
re_comp, re_exec - BSD regex functions SYNOPSIS
#define _REGEX_RE_COMP #include <sys/types.h> #include <regex.h> char *re_comp(char *regex); int re_exec(char *string); DESCRIPTION
re_comp() is used to compile the null-terminated regular expression pointed to by regex. The compiled pattern occupies a static area, the pattern buffer, which is overwritten by subsequent use of re_comp(). If regex is NULL, no operation is performed and the pattern buffer's contents are not altered. re_exec() is used to assess whether the null-terminated string pointed to by string matches the previously compiled regex. RETURN VALUE
re_comp() returns NULL on successful compilation of regex otherwise it returns a pointer to an appropriate error message. re_exec() returns 1 for a successful match, zero for failure. CONFORMING TO
4.3BSD. NOTES
These functions are obsolete; the functions documented in regcomp(3) should be used instead. SEE ALSO
regcomp(3), regex(7), GNU regex manual COLOPHON
This page is part of release 3.27 of the Linux man-pages project. A description of the project, and information about reporting bugs, can be found at http://www.kernel.org/doc/man-pages/. GNU
1995-07-14 RE_COMP(3)
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