I wish to write a bash script to check both columns and output a 1 if col1==1 AND col2<3. Otherwise I want to output a 0. In the above example, the result would be:
0
0
1
0
0
My script:
The echo $type and echo $time statements are in there to ensure the file is read correctly, which it seems to be. However my results are all 0s:
0
0
0
0
0
So my condition statement is never evaluating to true. Can anyone explain why?
Also if there's a better solution to this problem I'd be glad to here it - output can be in another file (as above) or recoded into another column of the same file, I don't really care.
Hi all,
I ve a script like....
TBL=employee
sql=`cat abhi.sql` \\ abhi.sql contains ------- select a from $TBL
echo $TBL
echo $sql
SQL=`echo $sql`
echo $SQL
now i want SQL as select a from employee
and as select a from $TBL
How can I achieve this?
Help appriciated (3 Replies)
I have a user defined configuration file, which could contain the following type of entries:
directory_001=/a/directory/structure
pattern_001=fred*
pattern_002=*
I have a script which reads the file generically which will loop round
loop 1
genvar=”directory”
iteration=”001”
... (11 Replies)
how do i evaluate the value of date
if ( $(date +%m) > 8 ) then
FY_STAMP=FY$(echo $(($(date +%Y) + 1)) | cut -c3-4)
else
FY_STAMP=FY$(date +%y)
fi
i want this to make the FY_STAMP increment by 1 if the month is september and up. but cant seem to make it work (3 Replies)
I have the following in my makefile:
RESULT=`../${TOOLS_ROOT_PATH}/ext_tools.sh 11`; \
set $$RESULT > tMp; \
rm tMp; \
if ; then \
echo copying external-local tool: $< \($$*\); \
mkdir -p ${EXTERNAL_LOCAL_BIN_DIR}/$<; \
cp -f... (4 Replies)
Does anyone know of a way to force a variable name held in another variable to return the value of the first variable? Best if I give an example, that does not work:
/usr/local/bin >cat mike.sh
NUM1ref=16
NUM2ref=32
echo "=============="
for VAR in NUM1 NUM2
do
XXXX=${VAR}ref
echo $XXXX... (4 Replies)
Hi Guys,
Good day ULF :) I hope you can help me again with my problem. I have a file which looks like this:
Command was launched from partition 0.
------------------------------------------------
Executing command in server server3
Dec 18 21:31:12 AHM04 nseventmgr: EVENT-SET:... (4 Replies)
Hi ,
getting error in below code
integer expression expected. its due to floating point. plz help me to solve this
ADV1=94.3
Quantity=96.3
if ; then
echo "quantity is greter"
fi (6 Replies)
I am trying to run following condition with both variables having numeric values "1,2,3"
if ;when i run it i get following error:
$NEW_STATE: integer expression expected
Please correct me where I'm doing wrong.
I'm trying to check either New State is greater or Old state.... (0 Replies)
Hi All,
I'm assigning a numeric value to variable count=2, well its being assigned by code above the if condition.
I want to test for 2 conditions , when $count = 0 or $count <=2 and do something when the condition matches. here is my code, but i run into the infamous :
if ]
then
... (2 Replies)
First, given this bit of code (line numbers included for reference:
59 get_all_db () {
60 #echo getting all db
61 dblist=`egrep -i "product/12" /etc/oratab |grep -v "listener"|\
62 awk -F\: '{print $1}'|sort`
63 echo list is $dblist
64 echo
65 echo
66 echo "INSTANCE_NAME ... (15 Replies)