Counting lines of code in a directory with awk Post: 302442555

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LEARN ABOUT DEBIAN

shtool-path

SHTOOL-PATH.TMP(1)					      GNU Portable Shell Tool						SHTOOL-PATH.TMP(1)

NAME

       shtool-path - GNU shtool command dealing with shell path variables

SYNOPSIS

       shtool path [-s|--suppress] [-r|--reverse] [-d|--dirname] [-b|--basename] [-m|--magic] [-p|--path path] str [str ...]

DESCRIPTION

       This command deals with shell $PATH variables. It can find a program through one or more filenames given by one or more str arguments.  It
       prints the absolute filesystem path to the program displayed on "stdout" plus an exit code of 0 if it was really found.

OPTIONS

       The following command line options are available.

       -s, --suppress
	   Supress output. Useful to only test whether a program exists with the help of the return code.

       -r, --reverse
	   Transform a forward path to a subdirectory into a reverse path.

       -d, --dirname
	   Output the directory name of str.

       -b, --basename
	   Output the base name of str.

       -m, --magic
	   Enable advanced magic search for ""perl"" and ""cpp"".

       -p, --path path
	   Search in path. Default is to search in $PATH.

EXAMPLE

	#   shell script
	awk=`shtool path -p "${PATH}:." gawk nawk awk`
	perl=`shtool path -m perl`
	cpp=`shtool path -m cpp`
	revpath=`shtool path -r path/to/subdir`

HISTORY

       The GNU shtool path command was originally written by Ralf S.  Engelschall <rse@engelschall.com> in 1998 for Apache. It was later taken
       over into GNU shtool.

SEE ALSO

       shtool(1), which(1).

18-Jul-2008							   shtool 2.0.8 						SHTOOL-PATH.TMP(1)

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