Hi All,
i have an small issue...
echo " "
eval x=$@
export x=`echo $x`
echo $x
ssh user@ipadrss; cd /mbbv/home/;
cd /mbbv/home/orange/orange/
echo pwd
bash samplescript.sh $x
above is my script which will triger from server A and will connect to server B for some... (2 Replies)
Hi,
When I run the command acroread it is giving error
ERROR: Cannot find installation directory.
When I look at /usr/local/Adobe/Acrobat7.0/bin/ an exicutable file named acroread is there. When i run ./acroread from that directory it is working . What can i do so that I can give... (3 Replies)
Hello
when i am giving a command apt-get install
I am getting error as below:
" apt-get: error while loading shared libraries: libapt-pkg-libc6.3-6.so.3.11: cannot open shared object file: No such file or directory "
can u suggest what to do.
https://www.unix.com/images/misc/progress.gif... (1 Reply)
I have FreeBSD installed with Xarchiver and when extracting files through the file manager ("Extract here..." option) the following error pops up: tar: unrecognized option `--overwrite'
Perhaps this is a known error and is there a way to solve it? (10 Replies)
Hi all,
Could someone please to tell me when do we exactly get the below error and how to get rid of it.
I am unable to trace the error.
(standard_in) 1: parse error
Thanks in advance !! (4 Replies)
Hi,
I am trying to make a script that tries to compare two values and print if one is greater than another. It seems to return a (standard_in) 1: parse error at times.
#!/bin/sh
a= awk '{print $1}' file1.txt
b= awk '{print $1}' file2.txt
c= awk '{print $1}' file3.txt
x= awk '{print... (5 Replies)
Hi,
I have an if condition on executing it is giving syntax error as below:
--------------------------------------------------------------------------------------
line 61: syntax error in conditional expression
./play_test.sh: line 61: syntax error near `]'
./play_test.sh: line 61: ` if... (2 Replies)
I created a shell script to record server temperature. When I manually run script it works fine with no error message. But when I create a cron job, my script fails with error message (standard_in)1:syntax error. I figured out the bc utility is causing the error message. Below is my script.
... (7 Replies)
Discussion started by: SysAdminRialto
7 Replies
LEARN ABOUT PHP
eval
EVAL(3) 1 EVAL(3)eval - Evaluate a string as PHP codeSYNOPSIS
mixed eval (string $code)
DESCRIPTION
Evaluates the given $code as PHP.
Caution
The eval(3) language construct is very dangerous because it allows execution of arbitrary PHP code. Its use thus is discouraged.
If you have carefully verified that there is no other option than to use this construct, pay special attention not to pass any user
provided data into it without properly validating it beforehand.
PARAMETERS
o $code
- Valid PHP code to be evaluated. The code mustn't be wrapped in opening and closing PHP tags, i.e. 'echo "Hi!";' must be passed
instead of '<? echo "Hi!"; >'. It is still possible to leave and reenter PHP mode though using the appropriate PHP tags, e.g.
'echo "In PHP mode!"; ?>In HTML mode!<? echo "Back in PHP mode!";'. Apart from that the passed code must be valid PHP. This
includes that all statements must be properly terminated using a semicolon. 'echo "Hi!"' for example will cause a parse error,
whereas 'echo "Hi!";' will work. A return statement will immediately terminate the evaluation of the code. The code will be exe-
cuted in the scope of the code calling eval(3). Thus any variables defined or changed in the eval(3) call will remain visible
after it terminates.
RETURN VALUES eval(3) returns NULL unless return is called in the evaluated code, in which case the value passed to return is returned. If there is a
parse error in the evaluated code, eval(3) returns FALSE and execution of the following code continues normally. It is not possible to
catch a parse error in eval(3) using set_error_handler(3).
EXAMPLES
Example #1
eval(3) example - simple text merge
<?php
$string = 'cup';
$name = 'coffee';
$str = 'This is a $string with my $name in it.';
echo $str. "
";
eval("$str = "$str";");
echo $str. "
";
?>
The above example will output:
This is a $string with my $name in it.
This is a cup with my coffee in it.
NOTES
Note
Because this is a language construct and not a function, it cannot be called using variable functions.
Tip
As with anything that outputs its result directly to the browser, the output-control functions can be used to capture the output of
this function, and save it in a string (for example).
Note
In case of a fatal error in the evaluated code, the whole script exits.
SEE ALSO call_user_func(3).
PHP Documentation Group EVAL(3)