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Top Forums UNIX for Dummies Questions & Answers How can i copy a list of files with different names into others directory have the same name? Post 302442105 by Franklin52 on Tuesday 3rd of August 2010 09:26:39 AM
Old 08-03-2010
You could play around with something like this:
Code:
filecnt=0

for file in 10_10*
do
  mkdir -f ../test2/${file}
  cp "$file" ../test2/${file}/
  filecnt=$(( $filecnt + 1 ))
done

echo "$filecnt files copied"

 

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GET_INCLUDED_FILES(3)							 1						     GET_INCLUDED_FILES(3)

get_included_files - Returns an array with the names of included or required files

SYNOPSIS
array get_included_files (void ) DESCRIPTION
Gets the names of all files that have been included using include(3), include_once(3), require(3) or require_once(3). RETURN VALUES
Returns an array of the names of all files. The script originally called is considered an "included file," so it will be listed together with the files referenced by include(3) and family. Files that are included or required multiple times only show up once in the returned array. EXAMPLES
Example #1 get_included_files(3) example <?php // This file is abc.php include 'test1.php'; include_once 'test2.php'; require 'test3.php'; require_once 'test4.php'; $included_files = get_included_files(); foreach ($included_files as $filename) { echo "$filename "; } ?> The above example will output: abc.php test1.php test2.php test3.php test4.php NOTES
Note Files included using the auto_prepend_file configuration directive are not included in the returned array. SEE ALSO
include(3), include_once(3), require(3), require_once(3), get_required_files(3). PHP Documentation Group GET_INCLUDED_FILES(3)
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