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Top Forums Shell Programming and Scripting How to remove lines before and after with awk / sed ? Post 302440933 by Franklin52 on Thursday 29th of July 2010 02:26:00 AM
Old 07-29-2010
Quote:
Originally Posted by ashimada
Hi guys,
I need to remove the pattern (ID=180), one line before and four lines after.
Thanks.
You can use grep if your grep version supports the -A and -B option, otherwise:
Code:
awk '/ID=180/{c=4;next}
c--<0 && p{print p}
{p=$0}
END{print p}
' file

This User Gave Thanks to Franklin52 For This Post:
 

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ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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