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Top Forums Shell Programming and Scripting How to remove lines before and after with awk / sed ? Post 302440933 by Franklin52 on Thursday 29th of July 2010 02:26:00 AM
Old 07-29-2010
Quote:
Originally Posted by ashimada
Hi guys,
I need to remove the pattern (ID=180), one line before and four lines after.
Thanks.
You can use grep if your grep version supports the -A and -B option, otherwise:
Code:
awk '/ID=180/{c=4;next}
c--<0 && p{print p}
{p=$0}
END{print p}
' file

This User Gave Thanks to Franklin52 For This Post:
 

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ZGREP(1)						    BSD General Commands Manual 						  ZGREP(1)

NAME
zgrep, zegrep, zfgrep -- print lines matching a pattern in gzip-compressed files SYNOPSIS
zgrep [grep-flags] [--] pattern [files ...] zegrep [grep-flags] [--] pattern [file ...] zfgrep [grep-flags] [--] pattern [file ...] DESCRIPTION
zgrep runs grep(1) on files or stdin, if no files argument is given, after decompressing them with zcat(1). The grep-flags and pattern arguments are passed on to grep(1). If an -e flag is found in the grep-flags, zgrep will not look for a pattern argument. zegrep calls egrep(1), while zfgrep calls fgrep(1). EXIT STATUS
In case of missing arguments or missing pattern, 1 will be returned, otherwise 0. SEE ALSO
egrep(1), fgrep(1), grep(1), gzip(1), zcat(1) AUTHORS
Thomas Klausner <wiz@NetBSD.org> BSD
December 28, 2003 BSD
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