Dear All:
I want to build a shell that delete files created two or more days ago ... I think it could be built using a special command with ls or grep, I'd apreciate any help from you guys
I have a lot of log files from november, december, january and this tool will help me a lot
The files... (3 Replies)
I need to find files that have the ending of .out and that are older than 20 days. However, I cannot use find as I do not want to search in the directories that are underneath the directory that I am searching in.
How can this be done?? Find returns files that I do not want. (2 Replies)
Our nightly updates run in the evening and finish around 8am. My boss wants the current log files kept on the server for 2 days, but wants anything created before noon, 2 days prior archived. I was thinking of using touch to set a temporary file with a date of today-2 and a time of noon, then... (3 Replies)
Hi All,
Could you please let me know if there is any one can help to create a shell script to remove some files which is the created date for them greate than 10 days (sysdate-10)
Please try to email me on email removed
Thanks in advance,
Murad (1 Reply)
Hi,
I have an application which creates some directories while running. I want to delete these directories which are 4 days older.
i tried
find . type d -mtime +1 -print
And it is working fine..
but
find . type d -mtime +4 -print
is not giving any results which are 4 days... (6 Replies)
Hello
I have some directories and files created under /export/local/user
I would like to delete directories only under /export/local/user, created before 3 days
Can someone help me with command to do this task?
Thanks (4 Replies)
Hi,
I want to find the sum of all the files created 5 days ago and store it in a variable. (os is HP-UX)
can this be extracted from ls -l
Is there any other way of getting the sum of all the files created (4 Replies)
Discussion started by: bang_dba
4 Replies
LEARN ABOUT DEBIAN
time::seconds
Time::Seconds(3perl) Perl Programmers Reference Guide Time::Seconds(3perl)NAME
Time::Seconds - a simple API to convert seconds to other date values
SYNOPSIS
use Time::Piece;
use Time::Seconds;
my $t = localtime;
$t += ONE_DAY;
my $t2 = localtime;
my $s = $t - $t2;
print "Difference is: ", $s->days, "
";
DESCRIPTION
This module is part of the Time::Piece distribution. It allows the user to find out the number of minutes, hours, days, weeks or years in a
given number of seconds. It is returned by Time::Piece when you delta two Time::Piece objects.
Time::Seconds also exports the following constants:
ONE_DAY
ONE_WEEK
ONE_HOUR
ONE_MINUTE
ONE_MONTH
ONE_YEAR
ONE_FINANCIAL_MONTH
LEAP_YEAR
NON_LEAP_YEAR
Since perl does not (yet?) support constant objects, these constants are in seconds only, so you cannot, for example, do this: "print
ONE_WEEK->minutes;"
METHODS
The following methods are available:
my $val = Time::Seconds->new(SECONDS)
$val->seconds;
$val->minutes;
$val->hours;
$val->days;
$val->weeks;
$val->months;
$val->financial_months; # 30 days
$val->years;
$val->pretty; # gives English representation of the delta
The usual arithmetic (+,-,+=,-=) is also available on the objects.
The methods make the assumption that there are 24 hours in a day, 7 days in a week, 365.24225 days in a year and 12 months in a year.
(from The Calendar FAQ at http://www.tondering.dk/claus/calendar.html)
AUTHOR
Matt Sergeant, matt@sergeant.org
Tobias Brox, tobiasb@tobiasb.funcom.com
BalieXXzs SzabieXX (dLux), dlux@kapu.hu
LICENSE
Please see Time::Piece for the license.
Bugs
Currently the methods aren't as efficient as they could be, for reasons of clarity. This is probably a bad idea.
perl v5.14.2 2011-09-19 Time::Seconds(3perl)