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Top Forums Shell Programming and Scripting highly specific search and replace for a large number of files Post 302438733 by ksubrama on Tuesday 20th of July 2010 03:26:59 PM
Old 07-20-2010
Yea .. good catch .. I forgot to type 'xargs' before grep ..
Code:
find . -type f -name *.c  | xargs grep -l foo

This did the right thing and found all the relevant files.

I probably did not mention that the 'bar' can appear anywhere in the foo command call and there is no specific pattern. Will I be able use wildcards in the pattern matching string for 's/' and say inside the foo command change all occurrences of bar? I tried using foo\(.*)bar pattern but i keep getting the signal 13 error from grep or unmatched ) error. I am surely missing something obvious here. pointers?

---------- Post updated at 03:26 PM ---------- Previous update was at 02:57 PM ----------

I went a step further now ... I tried the following:
Code:
perl -ie 's/foo.*?bar/foo.*?bar1/'

It matched the proper pattern but instead of replacing the existing contents and only replacing bar with bar1, it replaced the whole thing with 'foo.*?bar1' which is not what I wanted.
Code:
foo(blah,blah,blah,bar,blah,blah)

should be changed to
Code:
foo(blah,blah,blah,bar1,blah,blah)

The number of blah's varies widely. How do I make it replace the pattern properly?

Last edited by Franklin52; 07-20-2010 at 04:47 PM.. Reason: Please use code tags
 

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SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)
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