lets just say your cron output is stored in a file named file1
then you can use something like this:-
this will place all the lines before the date 2010/07/10 into file0. but in this case you have to enter the date manually. i mean the date 10days earlier date. or you can take it as a parameter. or pass it via giving output of find command.
I was wondering can anyone give me a clue how to start script which would do the following:
I have 2 numbers as input for example: 100 and 1000 and I need to create file and in that file should be written
100 - 199
200 - 299
300 - 399
400 - 499
500 - 599
600 - 699
700 - 799... (3 Replies)
does any one have any ideas how i would go about calculating the number of days left in the month from a bash script ?. I want to do some operations on a csv file according to the result (8 Replies)
I need a script to figure out if a user's last login was 90 days or older. OS=AIX 5.3, shell=Korn
Here's what I have so far:
====
#!/usr/bin/ksh
NOW=`lsuser -a time_last_login root | awk -F= '{ print $2 }'`
(( LAST_LOGIN_TIME = 0 ))
(( DIFF = $NOW - $LAST_LOGIN_TIME ))
lsuser -a... (3 Replies)
Hi Guys,
I was working some time ago n was in need to calculate date 30/31 days from today including Feb (Leap yr stuff). Today date is variable depending on day of execution of script. I tried searching but was not able to get exactly what I needed....So at that I time I implemented by my own... (3 Replies)
Hello,
I'm trying to create a shell script (#!/bin/sh) which should tell me the age of a file in minutes...
I have a process, which delivers me all 15 minutes a new file and I want to have a monitoring script, which sends me an email, if the present file is older than 20 minutes.
To do... (10 Replies)
I extract dates from the log file and need to calculate days between two dates. My dates are in yyyyMmmdd format. Example:
$d1=2011 Oct 21
$d2=2012 Feb 20
I need to calculate the number of days between $d2 and $d1. This is on Solaris.
Any ideas?
Thanks,
djanu (4 Replies)
I am unable to get this KSH script to work. Can someone help. I've been told this should work with KSH93. Which I think I have on Solaris 10.
If I do a grep -i version /usr/dt/bin/dtksh I get
@(#)Version M-12/28/93d
@(#)Version 12/28/93
@(#)Version M-12/28/93
This is correct for... (5 Replies)
I wrote the day calculator also in bash. I would like to now, that is it good so?
#!/bin/bash
datum1=`date -d "1991/1/1" "+%s"`
datum2=`date "+%s"`
diff=$(($datum2-$datum1))
days=$(($diff/(60*60*24)))
echo $days
Thanks in advance for your help! (3 Replies)
Hi,
I have one .csv file. I have 2 date columns present in file, column 2 and column 3.
I need to calculate how many days exist between 2 dates.
I am trying to subtract date column 2 from date column 3.
Eg: my file look likes
s.no, Start_date,End_Date
1, 7/29/2012,10/27/2012
2,... (9 Replies)
Discussion started by: Dimple
9 Replies
LEARN ABOUT PHP
datetime.setdate
DATETIME.SETDATE(3) 1 DATETIME.SETDATE(3)DateTime::setDate - Sets the date
Object oriented style
SYNOPSIS
public DateTime DateTime::setDate (int $year, int $month, int $day)
DESCRIPTION
Procedural style
DateTime date_date_set (DateTime $object, int $year, int $month, int $day)
Resets the current date of the DateTime object to a different date.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $year
- Year of the date.
o $month
- Month of the date.
o $day
- Day of the date.
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
CHANGELOG
+--------+---------------------------------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+---------------------------------------------------+
| 5.3.0 | |
| | |
| | Changed the return value on success from NULL to |
| | DateTime. |
| | |
+--------+---------------------------------------------------+
EXAMPLES
Example #1
DateTime.setDate(3) example
Object oriented style
<?php
$date = new DateTime();
$date->setDate(2001, 2, 3);
echo $date->format('Y-m-d');
?>
Procedural style
<?php
$date = date_create();
date_date_set($date, 2001, 2, 3);
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2001-02-03
Example #2
Values exceeding ranges are added to their parent values
<?php
$date = new DateTime();
$date->setDate(2001, 2, 28);
echo $date->format('Y-m-d') . "
";
$date->setDate(2001, 2, 29);
echo $date->format('Y-m-d') . "
";
$date->setDate(2001, 14, 3);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-02-28
2001-03-01
2002-02-03
SEE ALSO DateTime.setISODate(3), DateTime.setTime(3).
PHP Documentation Group DATETIME.SETDATE(3)