Hi Experts
I need some help in static memory allocation in C. I have a program in which I declared 2 variables, one char array and one integer. I was little surprised to see the addresses of the variables.
First:
I got the addresses displayed as : 3219437172 3219437170
The above result is straight forward wherein the array a got 2 bytes allocated.
Second:
When I changed the program as below:
I got the addresses displayed as : 3219437172 3219437144
The array a got allocated 28 bytes when the declaration is for 3 bytes.
Hello!
First of all, forgive me for bad English.
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#include <stdlib.h>
#include<string.h>
#define... (1 Reply)
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Hi everyone,
I'm not new to C programming, but I'm having question regarding the memory allocation of a pointer variable which, for instance, will be declared in main(), but its memory will be allocated in subroutine.
To clearify my question, I provide a small working example:
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hello all..
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hi
in the following code, how the memory is allocated for a1 which holds the values of a2 after cpy function call.
#include <stdio.h>
#include <string.h>
void cpy(char* d, const char* s){
while(*d++=*s++);
}
main(){
char* a1;
char* a2="done";
cpy(a1,a2);
... (3 Replies)
Hello,
I am new to C++ programming, so I'm still getting a feel for things. I recently wrote a simple C++ program (to be used as a ROOT Macro) to conduct a statistical analysis of a varied version of the Monty Hall problem (code below). Basically, the programs runs a few simple calculations to... (7 Replies)
Discussion started by: Tyler_92
7 Replies
LEARN ABOUT DEBIAN
array
array(3) Library Functions Manual array(3)NAME
array - The array library interface
SYNTAX
#include <array.h>
DESCRIPTION
An allocated array variable keeps track of
o a (nonzero) pointer to a dynamically allocated region of memory;
o the number of bytes allocated (always positive); and
o the number of bytes initialized (between 0 and the number of bytes allocated).
There are two other possibilities for the state of an array variable: unallocated and failed. In both cases, there is no dynamically allo-
cated region of memory.
A new array variable is normally created as a static variable:
#include "array.h"
static array x;
At this point it is unallocated. The array library provides various allocation and inspection functions.
A new array variable can also be created dynamically. It must be initialized to all-0, meaning unallocated, before it is given to any of
the array functions. It must be returned to the unallocated (or failed) state, for example with array_reset, before it is destroyed. These
rules prevent all memory leaks.
Expansion and inspection
array x;
t* p1 = array_allocate(&x,sizeof(t),pos);
t* p2 = array_get(&x,sizeof(t),pos);
t* p3 = array_start(&x);
int64 len = array_length(&x,sizeof(t));
int64 bytes = array_bytes(&x);
Truncation and deallocation
array x;
array_truncate(&x,sizeof(t),len);
array_trunc(&x);
array_reset(&x);
array_fail(&x);
Comparison
array x;
array y;
if (array_equal(&x,&y))
/* arrays are equal... */
Concatenation
array x;
array y;
array_cat(&x,&y);
array_catb(&x,"fnord",5);
array_cats(&x,"fnord");
array_cats0(&x,"fnord"); /* also append the */
array_cat0(&x); /* append */
array_cate(&x,"fnord",1,4); /* append "nor" */
ORIGINAL API DEFINITION
http://cr.yp.to/lib/array.html
SEE ALSO array_get(3), array_start(3), array_fail(3)array(3)