Hello friends,
i wrote a script which includes a couple of if-else loops but i have to change it to while-do loop as it is not allowed to use "break" in if-else loop in bash.
#!/bin/bash -x
NUM=`find . -name ufsdump_output1.txt | xargs egrep "End-of-tape detected"`
if ; then echo "OK!"... (6 Replies)
i am new to shell scripting. this is similar to the code which i was writing for some other work. i want the variable 'x' to have the value which it will finally have at the end of the loop ( the number of directories ). but the value of 'x' only changes inside the loop and it remains '0' out-side... (3 Replies)
Hi to All,
Please find below details.
file_config.config
export file1_status="SUCCESS"
export file2_status="SUCCESS"
file_one.sh
I am calling another two shell script from these script. I need to pass individual two script status (If it's "FAILED") to file_main.sh.
file_main.sh
I... (2 Replies)
Simple enough problem I think, I just can't seem to get it right.
The below doesn't work as intended, it's just a function defined in a much larger script:
CheckValues() {
for field in \
Group_ID \
Group_Title \
Rule_ID \
Rule_Severity \
... (2 Replies)
I have a group of variables myLINEcnt1 - myLINEcnt10. I'm trying to printout the values using a for loop. I am at the head banging stage since i'm sure it has to be a basic syntax issue that i can't figure out.
For myIPgrp in 1 2 3 4 5 6 7 8 9 10; do
here i want to output the value of... (4 Replies)
Hi guys, i have an executable file that contains several records and fields. One of the records has a variable filed that must be changed each time i want to execute the file. Would it be possible that i can use a loop to change the value of that field? Suppose that the field address is:
Record... (5 Replies)
Hello All,
Maybe I'm Missing something here but I have NOOO idea what the heck is going on with this....?
I have a Variable that contains a PATTERN of what I'm considering "Illegal Characters". So what I'm doing is looping
through a string containing some of these "Illegal Characters". Now... (5 Replies)
Hi, I have an N number of files in a directory. I like to write a shell script that would make identical plots for each one of these files.
The files have names such as:
t00001.dat
t00002.dat
t00003.dat
t00004.dat
t00005.dat
.
.
.
t00040.dat
i.e. the... (4 Replies)
Hi All,
I have a file which has hundred of records with fixed number of fields. In each record there is set of 8 characters which represent the duration of that activity. I want to sum up the duration present in all the records for a report. The problem is the duration changes per record so I... (5 Replies)
In a "for i in *FD.CPY do" loop, I need to change .CPY to .layout so the executed command would be
reclay blahFD.CPY >blahFD.layout
What do I need to do to modify a copy of i to use after the > symbol?
TIA (5 Replies)
Discussion started by: wbport
5 Replies
LEARN ABOUT PHP
debug_zval_dump
DEBUG_ZVAL_DUMP(3) 1 DEBUG_ZVAL_DUMP(3)debug_zval_dump - Dumps a string representation of an internal zend value to outputSYNOPSIS
void debug_zval_dump (mixed $variable, [mixed $...])
DESCRIPTION
Dumps a string representation of an internal zend value to output.
PARAMETERS
o $variable
- The variable being evaluated.
RETURN VALUES
No value is returned.
EXAMPLES
Example #1
debug_zval_dump(3) example
<?php
$var1 = 'Hello World';
$var2 = '';
$var2 =& $var1;
debug_zval_dump(&$var1);
?>
The above example will output:
&string(11) "Hello World" refcount(3)
Note
Beware the refcount
The refcount value returned by this function is non-obvious in certain circumstances. For example, a developer might expect the
above example to indicate a refcount of 2. The third reference is created when actually calling debug_zval_dump(3).
This behavior is further compounded when a variable is not passed to debug_zval_dump(3) by reference. To illustrate, consider a
slightly modified version of the above example:
Example #2
<?php
$var1 = 'Hello World';
$var2 = '';
$var2 =& $var1;
debug_zval_dump($var1); // not passed by reference, this time
?>
The above example will output:
string(11) "Hello World" refcount(1)
Why refcount(1)? Because a copy of $var1 is being made, when the function is called.
This function becomes even more confusing when a variable with a refcount of 1 is passed (by copy/value):
Example #3
<?php
$var1 = 'Hello World';
debug_zval_dump($var1);
?>
The above example will output:
string(11) "Hello World" refcount(2)
A refcount of 2, here, is extremely non-obvious. Especially considering the above examples. So what's happening?
When a variable has a single reference (as did $var1 before it was used as an argument to debug_zval_dump(3)), PHP's engine opti-
mizes the manner in which it is passed to a function. Internally, PHP treats $var1 like a reference (in that the refcount is
increased for the scope of this function), with the caveat that if the passed reference happens to be written to, a copy is made,
but only at the moment of writing. This is known as "copy on write."
So, if debug_zval_dump(3) happened to write to its sole parameter (and it doesn't), then a copy would be made. Until then, the
parameter remains a reference, causing the refcount to be incremented to 2 for the scope of the function call.
SEE ALSO var_dump(3), debug_backtrace(3), References Explained, References Explained (by Derick Rethans).
PHP Documentation Group DEBUG_ZVAL_DUMP(3)