Hi!!,
my HP-UX - 10.2 compiler doesnt appear to support ANSI style of coding. On compiling my C code, it flags error messages like
error 1705: Function prototypes are an ANSI Feature
Is it a generic problem with the HP compiler or do I need to use some special switches on the command... (9 Replies)
Hi
From within a shell script my mailx doesnt seem to work...can somebody tell me what is wrong...
#!/bin/ksh
#Script to verify wheather all databases listed are up and running
#Script works with Oracle8 and above databases
#Script has to be run by ./scriptname
DBA=xiamin@unix.com
echo... (3 Replies)
Hi,
My name is vreddy and I am learning c language now and written one programme on vi editor.
how do I compile the programme please give me some advice and that would be helpfull for me.
thanks
vre (10 Replies)
I am unable to compile the programs, I am able to compile .pc to .c but later part of the compilation from .c to executalbe i am unable to do.
Here is the way i am doing
make -f $LIB_LIB/makefile.templ sample
I am getting the following errors, which environment and where to set to point... (1 Reply)
Hi All,
I am unable to exit from a shell script using the below code:
#!/bin/ksh
passchk()
(
if ;then
echo "Password validated"
else
echo "Wrong password Quiting the application..."
exit 0#not working
fi
)
passchk
(Note:"finalresult" passed to the passchk... (2 Replies)
Hi ,
I Am Getting The Below Error When Executing A Shell Script (Running Red Hat Linux 5 As Guest And Host Is Windows 7) Logging As Root User
!/bin/ksh: not found
This Are The Steps I am Following For Saving And Executing The Script File.
1).Opening Terminal
2).Issue Command vi... (2 Replies)
Hi,
Pleasse could someone advise why i'm getting this error below - No such file or directory
dev6:$ ls -ltr ReleaseManagement.sh
-rwxr-xr-x 1 dev fix 4830 Aug 22 11:13 ReleaseManagement.sh
dev6:$ ./ReleaseManagement.sh
: No such file or directory
dev6:$
thank you (2 Replies)
Discussion started by: venhart
2 Replies
9. Post Here to Contact Site Administrators and Moderators
Variable I have in my shell script
diff=$1$2.diff
id=$2
new=new_$diff
echo "My id is $1"
echo "I want to sync for user account $id"
##awk command I am using is as below
cat $diff | awk -F'~' ''$2 == "$id"' {print $0}' > $new
I could see value of $id is not passing to the awk... (0 Replies)
I have a shell script (.sh) and I want to pass a parameter value to the awk command but I am getting exception, please assist.
diff=$1$2.diff
id=$2 new=new_$diff
echo "My id is $1"
echo "I want to sync for user account $id"
##awk command I am using is as below
cat $diff | awk... (2 Replies)
Discussion started by: Ashunayak
2 Replies
LEARN ABOUT PHP
geoip_country_code3_by_name
GEOIP_COUNTRY_CODE3_BY_NAME(3) 1 GEOIP_COUNTRY_CODE3_BY_NAME(3)geoip_country_code3_by_name - Get the three letter country codeSYNOPSIS
string geoip_country_code3_by_name (string $hostname)
DESCRIPTION
The geoip_country_code3_by_name(3) function will return the three letter country code corresponding to a hostname or an IP address.
PARAMETERS
o $hostname
- The hostname or IP address whose location is to be looked-up.
RETURN VALUES
Returns the three letter country code on success, or FALSE if the address cannot be found in the database.
EXAMPLES
Example #1
A geoip_country_code3_by_name(3) example
This will print where the host example.com is located.
<?php
$country = geoip_country_code3_by_name('www.example.com');
if ($country) {
echo 'This host is located in: ' . $country;
}
?>
The above example will output:
This host is located in: USA
SEE ALSO geoip_country_code_by_name(3), geoip_country_name_by_name(3).
PHP Documentation Group GEOIP_COUNTRY_CODE3_BY_NAME(3)