Hi all,
I have many files that have 1 or more occurrences of the information I want. There are two distinct sets of information. I want get this info and place each occurrence in its own file.
The 3 lines before one set are
this grid
00 01 02
16 17 18
**40 lines of code I want to... (5 Replies)
Hi,
i want to extract the 'CREATE INDEX' or 'CREATE UNIQUE INDEX' statements from a ddl file and output each match to a separate file. i was looking around the net but couldnīt find anything.
a possible sed-script could be:
sed -n '/CREATE*INDEX*/,/COMMIT/p' filename.ddlbut i couldnīt find out... (11 Replies)
Hi
I have requirement to find nth occurrence in a file and capture data from with in lines (between lines)
Data in File.
<QUOTE>
<SESSION>
<ATTRIBUTE NAME='Parameter Filename' VALUE='file1.parm'/>
<ATTRIBUTE NAME='Service Name' VALUE='None'/>
</SESSION>
<SESSION>
<ATTRIBUTE... (6 Replies)
Hi all,
Here is my problem for which i am breaking my head for past three days..
I have parted command output as follows..
Model: ATA WDC WD5000AAKS-0 (scsi)
Disk /dev/sdb: 500GB
Sector size (logical/physical): 512B/512B
Partition Table: msdos
Number Start End Size Type ... (3 Replies)
performing this code to read from file and print each character in separate line
works well with ASCII encoded text
void
preprocess_file (FILE *fp)
{
int cc;
for (;;)
{ cc = getc (fp);
if (cc == EOF)
break;
printf ("%c\n", cc);
}
}
int
main(int... (1 Reply)
Bash/Oracle Linux 6.4
A basic requirement.
How can I get nth line of a file printed ? Can I use grep in this case ?
Example:
In the below file, 12th line is "Kernel parameter check passed for rmem_max" . I just want the 12 line to be printed.
# cat sometext.txt
Kernel version check... (2 Replies)
example of problem:
when I echo "$e" >> /home/cogiz/file.txt
result prints to file as:AA
BB
CC
I need it to save to file as this:AA BB CC
I know it's probably something really simple but any help would be greatly appreciated.
Thank You.
Cogiz (7 Replies)
Hi,
A beginner one.
my input.tab (tab-separated):
h1 h2 h3 h4 h5
item1 grpA 2 3 customer1
item2 grpB 4 6 customer1
item3 grpA 5 9 customer1
item4 grpA 0 0 customer2
item5 grpA 9 1 customer2
objective:
output a file for each customer ($5) with the item number ($1) only if $2 matches... (2 Replies)
Discussion started by: beca123456
2 Replies
LEARN ABOUT PLAN9
grep
GREP(1) General Commands Manual GREP(1)NAME
grep - search a file for a pattern
SYNOPSIS
grep [ option ... ] pattern [ file ... ]
DESCRIPTION
Grep searches the input files (standard input default) for lines (with newlines excluded) that match the pattern, a regular expression as
defined in regexp(6). Normally, each line matching the pattern is `selected', and each selected line is copied to the standard output.
The options are
-c Print only a count of matching lines.
-h Do not print file name tags (headers) with output lines.
-i Ignore alphabetic case distinctions. The implementation folds into lower case all letters in the pattern and input before interpre-
tation. Matched lines are printed in their original form.
-l (ell) Print the names of files with selected lines; don't print the lines.
-L Print the names of files with no selected lines; the converse of -l.
-n Mark each printed line with its line number counted in its file.
-s Produce no output, but return status.
-v Reverse: print lines that do not match the pattern.
Output lines are tagged by file name when there is more than one input file. (To force this tagging, include /dev/null as a file name
argument.)
Care should be taken when using the shell metacharacters $*[^|()= and newline in pattern; it is safest to enclose the entire expression in
single quotes '...'.
SOURCE
/sys/src/cmd/grep.c
SEE ALSO ed(1), awk(1), sed(1), sam(1), regexp(6)DIAGNOSTICS
Exit status is null if any lines are selected, or non-null when no lines are selected or an error occurs.
GREP(1)