I have the following
for(( i=1; 1<=2; i++))
do
e1=123 n1=123
e2=456 n2=456
coord= $e1,$n1
echo "coordinate=$coord"
done
exit
this echos
coordinate=123,123
I need it to loop so:
loop1
coord=$e1,$n1
loop2 (3 Replies)
Hi,
I'm attempting to take the following input list and create an output file as shown below. I've monkeyed around for long enough. Can anyone help?
NOTE: fs*** will be header and I want to get a count on NY**.
fs200a
NY7A
fs200b
NY7B
NY7B
NY7B
fs200c
NY7C
NY7C
NY7C
NY7C... (2 Replies)
Hi,
I need some help.
Shell script counter. i need to add condition to check if counter is more than 10 and longer than 3 hours? it runs every 5 mins. it only check count and send email right now.
it runs in cron as below
gregcount.ksh gregdb 10 > /tmp/gregcount.out 2> /tmp/gregcount.err
... (1 Reply)
Hi,
I am new to shell script. I want to count to Delimiter count for my source file. For that I have written script. When I tried to execute the script I could not able to view the results. It throws errors. I don't know what the problem is. My aim is I want to store the delimiter count in one... (4 Replies)
Dear all,
I have numerous dat files (a.dat, b.dat...) containing 500 numeric values each. I would like to count them, based on their range and obtain a histogram or a counter.
INPUT:
a.dat
1.3
2.16
0.34
......
b.dat
1.54
0.94
3.13
.....
... (2 Replies)
cat sport_by_month
Month : Jan
sport :Football
sport :Volleyball
Month: Feb
sport :BasketBall
sport: Cricket
sport: Fotball
Month: Mar
Month: APR
sport : Bowling
sport : Climbing
I need your help to have a script that count the number of sports per month and sorted by mont with... (7 Replies)
i having a file
xxxxxxxxxxxxxxx1234 ...........value can be change
xxxxxxxxxxxxxxx1235
xxxxxxxxxxxxxxxx1236
.
.
.
.
xxxxxxxxxxxxxxxxx1300 ...........value can be change
i want to cut last four characters of first line and last line and find the missing pattern.
output should... (4 Replies)
I have this file
1801,A1,2012-12-16 15:59:59.995,id2_3,ab,phoneC2-00,VOE,,,,,,,,,,,,,,,
1802,A1,2012-12-16 15:59:59.995,id2_3,ab=,phoneX1-01,BL,,,,,,,,,,,,,,,
1803,A1,2012-12-16 15:59:59.995,id2_3,ab,phone300,BL,,,,,,,,,,,,,,,
1804,A1,2012-12-16... (4 Replies)
Discussion started by: nikhil jain
4 Replies
LEARN ABOUT LINUX
zegrep
ZGREP(1) General Commands Manual ZGREP(1)NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)ZGREP(1)