Can someone please tell me how to modify/add to this code so that it recognizes UNIX command options (all beginning with "-") and executes the command with options?
#include<stdio.h>
#include<stdlib.h>
int main(int argc, char *argv)
{
int i;
system("stty -echo");
... (8 Replies)
I am looking to populate an (associated) array with a command line argument.
The command line would look something like this:
alert -action test -priority '10' -module test_module . . .
The associated array would look like this after the data is read in
flag=(action=test
priority=10... (1 Reply)
my description from another thread...
here's my code:
#!/bin/bash
IFS=$'\n'
function OutputName() {
input=$1
echo $input
input=`echo "$input" | sed -e 's/.//'`
input=`echo "$input".avi`
output_name=$input
}
if ]; then
echo... (5 Replies)
so in unix this command works works and shows me a list of directories
find . -name \*.xls -exec dirname {} \; | sort -u | > list.txt
but when i try running a perl script to run this command
my $query = 'find . -name \*.xls -exec dirname {} \; | sort -u | > list.txt';... (2 Replies)
Hello everyone,
I have a perl script which takes various command line options from user like :
test.pl -i <input_file> -o <output_file> -d <value> -c <value>
Now I have multiple input files in a directory:
<input_file_1>
<input_file_2>
<input_file_3>
<input_file_4>
.....
....
...... (6 Replies)
Hi,
I am writing a shell script to build Java options dynamically in a variable array and pass them to java.exe. If an option value contains a space, I cannot find a way to get it interpreted correctly. Here is my example:
#!/bin/bash
JAVA_HOME=/opt/jvm/jre1.5.0_18
JAVA_OPTS=("-Xms256m... (4 Replies)
Being new to awk I have a really basic question. It just has to be in the archives but it didn't bite me when I went looking for it.
I've written an awk script, placed it in a file, added the "#!/usr/bin/awk -f" at the top of the script and away I go. "% myAwk <inputfile>" gives me exactly what... (2 Replies)
I'm reading about debugging aids in bash and have come across the set command. It says in my little book that an addition to typing
set
you can also use them "on the command line when running a script..." and it lists this in a small table:
set -o option Command Line... (5 Replies)
I have the following code and I am calling it using
./raytrac.bash -u
and getting problems. For some reason opt_usage is still 0.
opt_usage=0
iarg=0
narg=$#
while (($iarg < $narg))
do
(( iarg = $iarg + 1 ))
arg=$argv
usrInputFlag=`echo $arg | awk '/=/ {print 1}; ! /=/... (22 Replies)
Hi All,
I am new to scripting. Could you please assist me .
Here is my requirement. I have written a script that has 2 option flags defined.
-l) calls some function with the arguments passed in front of -l
-r) calls second function with the arguments passed in front of -r
*) calls the... (7 Replies)
Discussion started by: Jay Deshpande
7 Replies
LEARN ABOUT SUNOS
getopt
getopt(1) User Commands getopt(1)NAME
getopt - parse command options
SYNOPSIS
set -- ` getopt optstring $ * `
DESCRIPTION
The getopts command supersedes getopt. For more information, see NOTES below.
getopt is used to break up options in command lines for easy parsing by shell procedures and to check for legal options. optstring is a
string of recognized option letters; see getopt(3C). If a letter is followed by a colon (:), the option is expected to have an argument
which may or may not be separated from it by white space. The special option - is used to delimit the end of the options. If it is used
explicitly, getopt recognizes it; otherwise, getopt generates it; in either case, getopt places it at the end of the options. The posi-
tional parameters ($1 $2 ...) of the shell are reset so that each option is preceded by a - and is in its own positional parameter; each
option argument is also parsed into its own positional parameter.
EXAMPLES
Example 1: Processing the arguments for a command
The following code fragment shows how one might process the arguments for a command that can take the options -a or -b, as well as the
option -o, which requires an argument:
set -- `getopt abo: $*`
if [ $? != 0 ]
then
echo $USAGE
exit 2
fi
for i in $*
do
case $i in
-a | -b) FLAG=$i; shift;;
-o) OARG=$2; shift 2;;
--) shift; break;;
esac
done
This code accepts any of the following as equivalent:
cmd -aoarg filename1 filename2
cmd -a -o arg filename1 filename2
cmd -oarg -a filename1 filename2
cmd -a -oarg -- filename1 filename2
ATTRIBUTES
See attributes(5) for descriptions of the following attributes:
+-----------------------------+-----------------------------+
| ATTRIBUTE TYPE | ATTRIBUTE VALUE |
+-----------------------------+-----------------------------+
|Availability |SUNWcsu |
+-----------------------------+-----------------------------+
|CSI |enabled |
+-----------------------------+-----------------------------+
SEE ALSO intro(1), getopts(1), getoptcvt(1), sh(1), shell_builtins(1), getopt(3C), attributes(5)DIAGNOSTICS
getopt prints an error message on the standard error when it encounters an option letter not included in optstring.
NOTES
getopt will not be supported in the next major release. For this release a conversion tool has been provided, namely, getoptcvt. For more
information, see getopts(1) and getoptcvt(1).
Reset optind to 1 when rescanning the options.
getopt does not support the part of Rule 8 of the command syntax standard (see intro(1)) that permits groups of option-arguments following
an option to be separated by white space and quoted. For example,
cmd -a -b -o "xxx z yy" filename
is not handled correctly. To correct this deficiency, use the getopts command in place of getopt.
If an option that takes an option-argument is followed by a value that is the same as one of the options listed in optstring (referring to
the earlier EXAMPLES section, but using the following command line:
cmd -o -a filename
getopt always treats it as an option-argument to -o; it never recognizes -a as an option. For this case, the for loop in the example shifts
past the filename argument.
SunOS 5.10 7 Jan 2000 getopt(1)