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Top Forums Shell Programming and Scripting Want to grep for a pattern and display the content above that pattern Post 302432486 by panyam on Friday 25th of June 2010 06:03:47 AM
Old 06-25-2010
Quote:
Originally Posted by ajayakunuri
Hi,
Thanks for your replies, but they dint work Smilie

@panyam: It is displaying all the lines before that. i did a wc -l and here is the output
[cmg-iqdps2p0] x772525 /usr/prod/bdw/log> awk 'c&&c--;/FAILED/{c=50;print p;exit}{p=p"\n"$0}' dm_distwatch10r.20100624.log|wc -l
621
Sorry , misread it.

Something like this:

Code:
  
awk '/FAILED/{print p;exit} {p=p"\n"$0}' input_file | tail -50

 

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QSTAIL(1)							  qstail man page							 QSTAIL(1)

NAME
qstail - Utility prints the end of a log file starting at the specified pattern. SYNOPSIS
qstail -i <path> -p <pattern> DESCRIPTION
qstail shows the end of a log file beginning with the line containing the specified pattern. This may be used to show all lines which has been written after a certain event (e.g., server restart) or time stamp. OPTIONS
-i <path> Input file to read the data from. -p <pattern> Search pattern (literal string). SEE ALSO
qsexec(1), qsfilter2(1), qsgeo(1), qsgrep(1), qslog(1), qslogger(1), qspng(1), qsrotate(1), qssign(1) AUTHOR
Pascal Buchbinder, http://opensource.adnovum.ch/mod_qos/ mod_qos utilities 10.8 June 2012 QSTAIL(1)
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