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Top Forums Shell Programming and Scripting Want to grep for a pattern and display the content above that pattern Post 302432240 by panyam on Thursday 24th of June 2010 09:53:57 AM
Old 06-24-2010
Something like this:

Code:
 
awk 'c&&c--;/FAILED/{c=50;print p;exit}{p=p"\n"$0}' log_file

Forget to say : this is suggested by one of this forum member some time back ( few months).

Last edited by panyam; 06-24-2010 at 11:06 AM..
 

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