It sounds so easy to do.
I have a file thats laid out like this..
number text text text text (etc about 15 times with various text fields)
I want to take the first field, "number", subtract 100 from it, and then put it back in the file. a simple little manipulation of the first field in... (4 Replies)
I need to achieve the following.....I seached the forum but could not find it...
This is I have in a file...
"CH","TIA","10/27/2006",000590
I need the date in the third field to be attached to fileas 20061027_test.txt
How do I do it. (6 Replies)
HI,
I'm comparing my file date with the system date and if both the dates are equal I'm doing some operation. I use two variables for these two dates. I use the following command in my query. if ....
But here the current date $cd shows 01 and filedate $fdate shows 1. The file is created on 1 of ... (6 Replies)
Hi Gurus,
How to minus 15 minuets from current system time.
For example if current time is " Wed Oct 14 12:12:38 BST 2009", i need "Wed Oct 14 11:57:38 BST 2009"
Thanks (2 Replies)
How can i print a future time, so i get current time by date "+%H:M" but how can i say add 20 minutes to the current time and display as I have just done for current time. (1 Reply)
I have a file with a field containing the following:
"7/3/2009 7:07:12 PM","xxxx"
I need to be able to split this field up into two into a different format with the time being converted into 24 hour:
so that i can get the following:
"20090307","19:07:12","xxxx" (8 Replies)
In my shell script I take date as a input parameter from command line in the format "21 Oct 2011" which would be
date +'%d %b %Y'
Now i need to do two things here.
1) Validate the date entered by user
2) Calculate yesterday's date from the input. So in this case it should be: "20 Oct 2011"... (9 Replies)
I have a comma separated file containing numbers, I would like to read the file and divide each number by 1024 and create an output file.
Input file :
50312.00,3434.05, ,3433.34,124344.00,434343.00, , ,
Output file:
49.13,3.35,3.35,0,12.05,424.16,0,0
Please click this link: How to... (2 Replies)
I have a .CSV file (file.csv) whose data are all enclosed in double quotes. Sample format of the file is as below:
column1,column2,column3,column4,column5,column6, column7, Column8, Column9, Column10
"12","B000QRIGJ4","4432","string with quotes, and with a comma, and colon: in... (3 Replies)
Hallo Team
I can perform the task manually but i would like to automate this process. ok here goes. I have a perl script which runs every Wednesday every week and the name of the script is check_19.pl
This is how the script looks like :
#!/usr/bin/perl -w
#use strict;
use DBI;
#... (1 Reply)
Discussion started by: kekanap
1 Replies
LEARN ABOUT PHP
datetime.modify
DATETIME.MODIFY(3) 1 DATETIME.MODIFY(3)DateTime::modify - Alters the timestamp
Object oriented style
SYNOPSIS
public DateTime DateTime::modify (string $modify)
DESCRIPTION
Procedural style
DateTime date_modify (DateTime $object, string $modify)
Alter the timestamp of a DateTime object by incrementing or decrementing in a format accepted by strtotime(3).
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $modify
-A date/time string. Valid formats are explained in Date and Time Formats.
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
CHANGELOG
+--------+---------------------------------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+---------------------------------------------------+
| 5.3.6 | |
| | |
| | Absolute date/time statements now take effect. |
| | Previously, only relative parts were used. |
| | |
| 5.3.0 | |
| | |
| | Changed the return value on success from NULL to |
| | DateTime. |
| | |
+--------+---------------------------------------------------+
EXAMPLES
Example #1
DateTime.modify(3) example
Object oriented style
<?php
$date = new DateTime('2006-12-12');
$date->modify('+1 day');
echo $date->format('Y-m-d');
?>
Procedural style
<?php
$date = date_create('2006-12-12');
date_modify($date, '+1 day');
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2006-12-13
Example #2
Beware when adding or subtracting months
<?php
$date = new DateTime('2000-12-31');
$date->modify('+1 month');
echo $date->format('Y-m-d') . "
";
$date->modify('+1 month');
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-01-31
2001-03-03
SEE ALSO strtotime(3), DateTime.add(3), DateTime.sub(3), DateTime.setDate(3), DateTime.setISODate(3), DateTime.setTime(3), DateTime.setTimes-
tamp(3).
PHP Documentation Group DATETIME.MODIFY(3)