Hello,
The last line of prstat shows load average.
I am unable to figure out what actually it is.
I have read the man pages and also googled, all for no use.
Can somebody help me, as to what should be the avg. load of the system for best performance and how is this load of prstat calculated. (6 Replies)
Hi All,
Operating System and Version: SunOS,Solaris 10 sparc(64 bit)
RDBMS Version: 10.2.0.4.0
But the prstat logs of my system shows:-
NPROC USERNAME SWAP RSS MEMORY TIME CPU
83 cemsbin 5204M 3604M 22% 53:46:00 6.7%
2 adm 244M 240M 1.5% 15:13:53 3.5%
77 oracle 17G 10G 65% 4:24:47... (0 Replies)
Hi All,
But the prstat logs of my system shows:-
NPROC USERNAME SWAP RSS MEMORY TIME CPU
77 oracle 17G 10G 65% 4:24:47 0.8%
Total: 486 processes, 3850 lwps, load averages: 3.77, 4.45, 4.94
What does the MEMORY denotes?
Is it the %memory used from RAM?
Or is the %memory used by... (10 Replies)
Good Evening everyone,
I am confused about prstat O/P as it shows memory values which are different from actual value.Below is the O/P of prstat command and swap commands.
NPROC USERNAME SIZE RSS MEMORY TIME CPU
48 root 2113M 1590M 1.2% 45:09.39 32%
31 daemon ... (7 Replies)
hi all,
am writing a ksh script on solaris 9 to get the number of threads taken by a process. am using the prstat -p command to do this.
output i get is :
:"/export/home/user" > prstat -p 25528 | cut -f2 -d/
NLWP
203
Total: 1 processes, 203 lwps, load averages: 2.58, 3.24, 3.62... (2 Replies)
hi all,
was trying to figure out how busy my app was by looking at the performance of the app server. did a 'prstat -s rss' command to find the app servers using most memory.
Found a command 'prstat -m' which is meant to show more details on each pid but the output of this command... (1 Reply)
Hello
We have a SPARC box running Solaris 10. We have 32 GB of physical memory, 32 GB of swap. Now i want to monitor memory usage for performance tuning. The box is running Sybase database. When I type prstat i get the following
PID USERNAME SIZE RSS STATE PRI NICE TIME CPU... (4 Replies)
Is there any scripts to capture the process which use more than 5% CPU from prstat output? (9 Replies)
Discussion started by: tharmendran
9 Replies
LEARN ABOUT CENTOS
xfs_estimate
xfs_estimate(8) System Manager's Manual xfs_estimate(8)NAME
xfs_estimate - estimate the space that an XFS filesystem will take
SYNOPSIS
xfs_estimate [ -h ] [ -b blocksize ] [ -i logsize ]
[ -e logsize ] [ -v ] directory ...
xfs_estimate -V
DESCRIPTION
For each directory argument, xfs_estimate estimates the space that directory would take if it were copied to an XFS filesystem. xfs_esti-
mate does not cross mount points. The following definitions are used:
KB = *1024
MB = *1024*1024
GB = *1024*1024*1024
The xfs_estimate options are:
-b blocksize
Use blocksize instead of the default blocksize of 4096 bytes. The modifier k can be used after the number to indicate multiplica-
tion by 1024. For example,
xfs_estimate -b 64k /
requests an estimate of the space required by the directory / on an XFS filesystem using a blocksize of 64K (65536) bytes.
-v Display more information, formatted.
-h Display usage message.
-i, -e logsize
Use logsize instead of the default log size of 1000 blocks. -i refers to an internal log, while -e refers to an external log. The
modifiers k or m can be used after the number to indicate multiplication by 1024 or 1048576, respectively.
For example,
xfs_estimate -i 1m /
requests an estimate of the space required by the directory / on an XFS filesystem using an internal log of 1 megabyte.
-V Print the version number and exits.
EXAMPLES
% xfs_estimate -e 10m /var/tmp
/var/tmp will take about 4.2 megabytes
with the external log using 2560 blocks or about 10.0 megabytes
% xfs_estimate -v -e 10m /var/tmp
directory bsize blocks megabytes logsize
/var/tmp 4096 792 4.0MB 10485760
% xfs_estimate -v /var/tmp
directory bsize blocks megabytes logsize
/var/tmp 4096 3352 14.0MB 10485760
% xfs_estimate /var/tmp
/var/tmp will take about 14.0 megabytes
xfs_estimate(8)