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Full Discussion: extract last part of string.
Top Forums Shell Programming and Scripting extract last part of string. Post 302430335 by vprasads on Thursday 17th of June 2010 09:40:28 AM
Old 06-17-2010
extract last part of string.

Hi,

I have a string like this

BUNDLE=/home/bob/flx/user.bun

how to extract only the the last part ie, only user.bun
 

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.K5LOGIN(5)							File Formats Manual						       .K5LOGIN(5)

NAME
.k5login - Kerberos V5 acl file for host access. DESCRIPTION
The .k5login file, which resides in a user's home directory, contains a list of the Kerberos principals. Anyone with valid tickets for a principal in the file is allowed host access with the UID of the user in whose home directory the file resides. One common use is to place a .k5login file in root's home directory, thereby granting system administrators remote root access to the host via Kerberos. EXAMPLES
Suppose the user "alice" had a .k5login file in her home directory containing the following line: bob@FUBAR.ORG This would allow "bob" to use any of the Kerberos network applications, such as telnet(1), rlogin(1), rsh(1), and rcp(1), to access alice's account, using bob's Kerberos tickets. Let us further suppose that "alice" is a system administrator. Alice and the other system administrators would have their principals in root's .k5login file on each host: alice@BLEEP.COM joeadmin/root@BLEEP.COM This would allow either system administrator to log in to these hosts using their Kerberos tickets instead of having to type the root pass- word. Note that because "bob" retains the Kerberos tickets for his own principal, "bob@FUBAR.ORG", he would not have any of the privileges that require alice's tickets, such as root access to any of the site's hosts, or the ability to change alice's password. SEE ALSO
telnet(1), rlogin(1), rsh(1), rcp(1), ksu(1), telnetd(8), klogind(8) .K5LOGIN(5)
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