It's perhaps a dummy question... but I don't find my way!
1) When I put the date command in a variable, it is ok and here the code :
2) I should to get direct the date and not in a variable, like :
But here the result :
Hi,
I am trying to modify a script which accepts date in format dd/mm/yy. I am trying to modify the script so that it retrieves the date that was 15 days earlier from today as start date. Eg.if today is 05/09/2006, the script should retrieve 21/08/2006 as start date. Is there any script/code to... (2 Replies)
Doubt #1
I have a program that I want the user to input date. When the user inputs the date, is it able to format it to system date dd-mm-yyy and then echo the value into a text file?
Doubt#2
If the above is not going to work, I tried to have the system date appear in the user input field and... (6 Replies)
I need to increment a date value through shell script.
Input value consist of start date and end date in DATE format of unix.
For eg.
I need increment a date value of 1/1/09 to 31/12/09 i.e for a whole yr.
The output must look like
1/1/09
2/2/09
.
.
.
31/1/09
.
.
1/2/09
.
28/2/09... (1 Reply)
Im in EST, and im using the command
CurrentDate=`TZ="EST+24" date +'%y%m%d'`
to get the yesterday's date.
Does this work perfectly for the boundary conditions of month end or year end(leap year) etc ? (2 Replies)
Hi,
I want to compare today's date(DDMMYYYY) with yesterday(DDMMYYYY) from system date,if (today month = yesterday month) then execute alter query else do nothing.
The above requirement i want in Shell script(KSH)...
Can any one please help me?
Double post, continued here. (0 Replies)
I have a shell script (.sh) and I want to pass a parameter value to the awk command but I am getting exception, please assist.
diff=$1$2.diff
id=$2 new=new_$diff
echo "My id is $1"
echo "I want to sync for user account $id"
##awk command I am using is as below
cat $diff | awk... (2 Replies)
Hi ,
How would i write a shell script to run the code from one date to another date EXample 2014-01-01 to 2014-02-28, can i any provide some clue on this (4 Replies)
hi all,
How to compare two files whether they are same are not...? like i had my input files as 20141201_file.txt and 20141130_file2.txt
how to compare the above files based on date .. like todays file and yesterdays file...? (4 Replies)
Hi Community!
Following on from this code in another thread:
#!/bin/bash
file_string=`/bin/cat date.txt | /usr/bin/awk '{print $5,$4,$7,$6,$8}'`
file_date=`/bin/date -d "$file_string"`
file_epoch=`/bin/date -d "$file_string" +%s`
now_epoch=`/bin/date +%s`
if
then
#let... (2 Replies)
Discussion started by: Greenage
2 Replies
LEARN ABOUT PHP
datetime.format
DATETIME.FORMAT(3) 1 DATETIME.FORMAT(3)DateTime::format - Returns date formatted according to given format
Object oriented style
SYNOPSIS
public string DateTime::format (string $format)
DESCRIPTION
string DateTimeImmutable::format (string $format) string DateTimeInterface::format (string $format)
Procedural style
string date_format (DateTimeInterface $object, string $format)
Returns date formatted according to given format.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3)
o $format
- Format accepted by date(3).
RETURN VALUES
Returns the formatted date string on success or FALSE on failure.
EXAMPLES
Example #1
DateTime.format(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-01');
echo $date->format('Y-m-d H:i:s');
?>
Procedural style
<?php
$date = date_create('2000-01-01');
echo date_format($date, 'Y-m-d H:i:s');
?>
The above example will output:
2000-01-01 00:00:00
NOTES
This method does not use locales. All output is in English.
SEE ALSO date(3).
PHP Documentation Group DATETIME.FORMAT(3)