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Top Forums Shell Programming and Scripting date command in a shell script Post 302429724 by hiddenshadow on Tuesday 15th of June 2010 09:48:41 AM
Old 06-15-2010
date command in a shell script

It's perhaps a dummy question... but I don't find my way!
1) When I put the date command in a variable, it is ok and here the code :
Code:
WEEK_DAY=`date +%w`
DAY=`date +%Y%m%d`
echo  WEEK_DAY : "$WEEK_DAY"
echo  DAY : "$DAY"

2) I should to get direct the date and not in a variable, like :
Code:
echo "DAY : `date +%Y%m%d`"

But here the result :
Quote:
./send_trap.sh: line 26: date: command not found
trying with sh,ksh and bash... same result!

What's happen? as someone an idea?
 

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DATETIME.FORMAT(3)							 1							DATETIME.FORMAT(3)

DateTime::format - Returns date formatted according to given format

       Object oriented style

SYNOPSIS
public string DateTime::format (string $format) DESCRIPTION
string DateTimeImmutable::format (string $format) string DateTimeInterface::format (string $format) Procedural style string date_format (DateTimeInterface $object, string $format) Returns date formatted according to given format. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3) o $format - Format accepted by date(3). RETURN VALUES
Returns the formatted date string on success or FALSE on failure. EXAMPLES
Example #1 DateTime.format(3) example Object oriented style <?php $date = new DateTime('2000-01-01'); echo $date->format('Y-m-d H:i:s'); ?> Procedural style <?php $date = date_create('2000-01-01'); echo date_format($date, 'Y-m-d H:i:s'); ?> The above example will output: 2000-01-01 00:00:00 NOTES
This method does not use locales. All output is in English. SEE ALSO
date(3). PHP Documentation Group DATETIME.FORMAT(3)
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