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Full Discussion: Traversing in Array of pointers
Top Forums Programming Traversing in Array of pointers Post 302428314 by Corona688 on Wednesday 9th of June 2010 12:51:53 PM
Old 06-09-2010
Quote:
Originally Posted by ramkrix
Thanks for the quick reply. I wll use this. Howevr, I have one more question. Here from the declaration of char *s[], we are easily able to note that there 6 "pointer to char arrays" and using a variable as suggested by you, we can traverse. Is there any other way, such that I am not using any variable line "n" to traverse.

I am asking like this:
we have '\0' character to say "end of string" and we use this character to traverse along string like (*sptr!='\0')
Similarly, do we have any thing to notify "end of pointer to character arrays" in Array of pointers.
Strings NULL-terminate themselves, but nothing else does, so your array is not NULL-terminated; it couldn't know when to stop. And each string is fully independent, the contents of one string won't help you find where the next begins.

If the array was NULL-terminated, you could do so like this:

Code:
# include <stdio.h>
# include <string.h>

int main(void)
{
char *s[] = {
"We will teach you how to..",
"Move a mountain",
"Level a building",
"Erase the past",
"Make a million",
"....all through C!",
NULL /* Needed to know where to stop! */
};

char **ptr=s;

while( (*ptr) != NULL)
{
  char *str=(*ptr);

  // count e's in str
  ...

  // move to next string
  ptr++;
}

}

 

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LEARN ABOUT OSX

strstr

STRSTR(3)						   BSD Library Functions Manual 						 STRSTR(3)

NAME

     strcasestr, strcasestr_l, strnstr, strstr -- locate a substring in a string

LIBRARY

     Standard C Library (libc, -lc)

SYNOPSIS

     #include <string.h>

     char *
     strcasestr(const char *s1, const char *s2);

     char *
     strnstr(const char *s1, const char *s2, size_t n);

     char *
     strstr(const char *s1, const char *s2);

     #include <string.h>
     #include <xlocale.h>

     char *
     strcasestr_l(const char *s1, const char *s2, locale_t loc);

DESCRIPTION

     The strstr() function locates the first occurrence of the null-terminated string s2 in the null-terminated string s1.

     The strcasestr() function is similar to strstr(), but ignores the case of both strings.

     The strnstr() function locates the first occurrence of the null-terminated string s2 in the string s1, where not more than n characters are
     searched.	Characters that appear after a '' character are not searched.  Since the strnstr() function is a FreeBSD specific API, it should
     only be used when portability is not a concern.

     While the strcasestr() function uses the current locale, the strcasestr_l() function may be passed a locale directly. See xlocale(3) for more
     information.

RETURN VALUES

     If s2 is an empty string, s1 is returned; if s2 occurs nowhere in s1, NULL is returned; otherwise a pointer to the first character of the
     first occurrence of s2 is returned.

EXAMPLES

     The following sets the pointer ptr to the "Bar Baz" portion of largestring:

	   const char *largestring = "Foo Bar Baz";
	   const char *smallstring = "Bar";
	   char *ptr;

	   ptr = strstr(largestring, smallstring);

     The following sets the pointer ptr to NULL, because only the first 4 characters of largestring are searched:

	   const char *largestring = "Foo Bar Baz";
	   const char *smallstring = "Bar";
	   char *ptr;

	   ptr = strnstr(largestring, smallstring, 4);

SEE ALSO

     memchr(3), strchr(3), strcspn(3), strpbrk(3), strrchr(3), strsep(3), strspn(3), strtok(3), wcsstr(3), xlocale(3)

STANDARDS

     The strstr() function conforms to ISO/IEC 9899:1990 (``ISO C90'').

BSD
								 October 11, 2001							       BSD
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