hi all,
I'm trying to do a cp only on files I created on a given day or within a certain date range.
What's the best way to do this?
Cheers,
KL (1 Reply)
Hi Experts,
I have files name
report_20090416
report_20090417
report_20090418
report_20090420
report_20090421
I have 2 input from user
From Date: 20090417
To Date: 20090420
and I need to grep only those line in between. Output should be
report_20090417
report_20090418... (3 Replies)
Hi ,
I need a function that verfies the given date is between start date and end date .
I have written this but this not working if start date is 1900/01/01
Below is my code
validateDate()
{
RC=$#
if
then
return 0
else
... (2 Replies)
I have a number of instances wher I need to run reports for the previous month and need to include the last months date range in the sql.
I want to create a string which consists of the first and last dates of last month separated with an ' and ' ie for this month (Feb) I want it to say
'01/01/10... (3 Replies)
Hi All,
Can anybody help me out a Shell script which pulls the files based on date range
Example
./test.sh start_date End_date (20110901 20110930)
or
./test.sh ( if we don't provide any input)
it should take sysdate-1 ( yesterdays date)
it should have both conditions
Plzz help me... (1 Reply)
Hi Everyone How all are doing today,
Want some help from All in Unix, What I am trying to do is , A shell file should be a called with two date parameters suppose the shell file name is run.sh
run.sh <start_date> <end_date>
If end date is not given it will pick today's date. The date should... (7 Replies)
Solaris 10
ksh88
Sorry for re-hashing some of this, but I can't find a proper solution in the forums.
Starting with /a/archive containing (on and on date formatted directories)
20060313 20080518 20100725 20121015
20060314 20080519 ... (1 Reply)
Hi
i am try to run a script by using a dates here is what i am doing
EXPORTDATE=`date --date "2 days ago" +%Y-%m-%d`
sh /path/to/the/files.sh ${EXPORTDATE}
the above code runs the job for one day,if i want to run the job for all the past 4 days how can i pass the date as a... (1 Reply)
My unix version is IBM AIX Version 6.1
I tried google my requirement and found the below answer,
find . -newermt “2012-06-15 08:13" ! -newermt “2012-06-15 18:20"
But newer command is not working in AIX version 6.1 unix
I have given my requirement below:
Input:
atr files:
... (1 Reply)
Dear all,
how can I select in the file below only the files created between Aug 14 2014 and Feb 03 2015?
EZA2284I -rw-r--r-- 1 30 8 356954 Aug 15 2014 file1
EZA2284I -rw-rw-r-- 1 30 8 251396 Feb 05 12:53 file2
EZA2284I -rw-rw-r-- 1 30 8 ... (3 Replies)
Discussion started by: simomuc
3 Replies
LEARN ABOUT PHP
datetime.setdate
DATETIME.SETDATE(3) 1 DATETIME.SETDATE(3)DateTime::setDate - Sets the date
Object oriented style
SYNOPSIS
public DateTime DateTime::setDate (int $year, int $month, int $day)
DESCRIPTION
Procedural style
DateTime date_date_set (DateTime $object, int $year, int $month, int $day)
Resets the current date of the DateTime object to a different date.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $year
- Year of the date.
o $month
- Month of the date.
o $day
- Day of the date.
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
CHANGELOG
+--------+---------------------------------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+---------------------------------------------------+
| 5.3.0 | |
| | |
| | Changed the return value on success from NULL to |
| | DateTime. |
| | |
+--------+---------------------------------------------------+
EXAMPLES
Example #1
DateTime.setDate(3) example
Object oriented style
<?php
$date = new DateTime();
$date->setDate(2001, 2, 3);
echo $date->format('Y-m-d');
?>
Procedural style
<?php
$date = date_create();
date_date_set($date, 2001, 2, 3);
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2001-02-03
Example #2
Values exceeding ranges are added to their parent values
<?php
$date = new DateTime();
$date->setDate(2001, 2, 28);
echo $date->format('Y-m-d') . "
";
$date->setDate(2001, 2, 29);
echo $date->format('Y-m-d') . "
";
$date->setDate(2001, 14, 3);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-02-28
2001-03-01
2002-02-03
SEE ALSO DateTime.setISODate(3), DateTime.setTime(3).
PHP Documentation Group DATETIME.SETDATE(3)