I know this must be really easy, but i can't get it to work
I've got a perl script, with a file.
I want to print an empty line, and the following doesn't seem to work:
print nameoffile "\n"
thanks for your help!! (3 Replies)
Hi all,
I have one CSV file(MasterFile.csv) consists of two columns.
"./incoming/ABC.CSV","./incoming/ABC_CONTROL.txt"
"./incoming/PQR.CSV","./incoming/PQR_CONTROL.txt"
"./incoming/123.CSV","./incoming/123_CONTROL.txt"
I have written a script to read the MasterFile.csv.Here i want to... (4 Replies)
How can i add new parameters into a line, and redirect the line to other file?
For example:
1.sh
name:owner
google:richard
youtube:student
I want a, for example 2.sh with:
name:owner:description
google:richard:search site
youtube:student:video site
In the 2.sh, I added a new column:... (7 Replies)
Hi,
I am new to Sed /awk commands. using that i want to add new empty line after every line in a file by leaving first three lines. So, can any one help me out how to achieve this.
Example:
---------
Input Filename: file1.txt
Input Data:
--------Report--------
Date:20-10-03... (4 Replies)
Hi How Are you?
I am doing fine!
I need to go now?
I will see you tomorrow!
Basically I need to replace the entire line containing "doing" with a blank line:
I need to the following output:
Hi How Are you?
I need to go now?
I will see you tomorrow!
Thanks in advance.... (1 Reply)
Hi, could you please help with the following:
I have an input file like:
one
two
three
four
five
six
I want to print the lines starting from 'three' to the empty line.
Something like that:
if ( line == "three" )
{
while ( !line.empty() )
{
cout <<... (0 Replies)
Hi,
I want to achieve something similar to what described in another post:
The difference is I want to add the line if the pattern is not found.
File 1:
A123, valueA, valueB
B234, valueA, valueB
C345, valueA, valueB
D456, valueA, valueB
E567, valueA, valueB
F678, valueA, valueB
... (11 Replies)
Hello,
I need a program that read a file line by line and prints out lines 1, 2 & 3 after an empty line... An example of entries in the file would be:
SRVXPAPI001 ERRO JUN24 07:28:34 1775
REASON= 0000, PROCID= #E506 #1065: TPCIPPR, INDEX= 003F
... (8 Replies)
Hello,
I am trying to remove everything coming after empty line under ubuntu14.04.
How may I do it?
file:
aaa
020390
bb00id3
c03wisi
209dl
x092sia
0290s
I expect:
aaa
020390
bb00id3
c03wisi (3 Replies)
Discussion started by: baris35
3 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)