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Top Forums Shell Programming and Scripting Variable is not evaluated in awk statement Post 302424666 by clx on Wednesday 26th of May 2010 03:21:58 AM
Old 05-26-2010
Welcome to the forum.

You never declared the variable "actual_code".
Btw, Not clear what you want to do with this variable.

regarding "$channel" and "$stake"

try using this:

Code:
awk -v c="$channel" -v s="$stake" '/c/ && /s/ {......}


Please use code tags next time ( select the code and press # in the toolbar).
This User Gave Thanks to clx For This Post:
 

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ARES_DUP(3)						     Library Functions Manual						       ARES_DUP(3)

NAME
ares_dup - Duplicate a resolver channel SYNOPSIS
#include <ares.h> int ares_dup(ares_channel *dest, ares_channel source) DESCRIPTION
The ares_dup(3) function duplicates an existing communications channel for name service lookups. If it returns successfully, ares_dup(3) will set the variable pointed to by dest to a handle used to identify the name service channel. The caller should invoke ares_destroy(3) on the handle when the channel is no longer needed. The ares_dup_options function also initializes a name service channel, with additional options set exactly as the source channel has them configured. SEE ALSO
ares_destroy(3), ares_init(3), ares_library_init(3) AVAILABILITY
ares_dup(3) was added in c-ares 1.6.0 AUTHOR
Daniel Stenberg 26 May 2009 ARES_DUP(3)
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