Hello,
I want to do a simple substitution using sed but I can't find a solution. Basically, from a Apache conf file, I would like to remove everything included between the <VirtualHost> and </VirtualHost> e.g
So the result I want is everything withtout the VirtualHost part:
I tried:
but it does not match the line block
I need to replace the line containing "STAGE_DB" with the line
"STAGE_DB $DB # database that contains the table being loaded ($workingDB)"
Here $DB is passed during the runtime.
How can I do this?
Thanks,
Kousikan (2 Replies)
Please help!
Input pattern, where ... could be any number of lines
struct A {
Blah1
Blah2
Blah3
...
} B;
output pattern
struct AB {
Blah1
Blah2
Blah3
...
};
I need help in extracting everything between { and }
if it would have been on a single line { \(.*\)} should have worked. (15 Replies)
I am searching a dhcpd.conf to find the hardware ethernet match, then once the match is found delete just the line above it. For example:
testmachine.example {
hardware ethernet 00:00:00:00:00:00;
fixed address 192.168.1.100;
next-server 192.168.1.101;
filename "linux-install/pxelinux.0";
}... (3 Replies)
the following range matching works great but i wish to add a blank line after each range result set... which i've tried and researched to no avail
MY INPUT DATA:
CURRENT CODE I'M USING:
sed -n '/*$/,/;/p' $INPUT_FILE
RESULTS I'M GETTING:
RESULT I looking to... (5 Replies)
New to sed...
Have a file foo.txt (below).
Need to replace text on 2 lines, but can only feed sed the first few characters of each line (all lines are unique).
So, in my example, I have put '$' in place of what I need to figure out how to feed the whole line.
What I have thus far:
sed -e... (6 Replies)
Hi,
I want to match a line which exists in a file. I have written a test script similar to below -
The content of the file file.txt would be like this -
/usr/bin/1234.xcf
/usr/bin/3456.xcf
/usr/bin/7897.xcf
/usr/bin/2345.xcf
out=`sed -n '\/usr\/bin\/7897.xcf/p' file.txt 2>&1`... (3 Replies)
Hi all,
This is my first post, so please go easy if I broke some rules. Not accustomed to posting in forums... :)
I'm looking for help on pattern matching within a multiline block and looking to highlight blocks/block-ids that do NOT contain a particular pattern.
For example an input file... (5 Replies)
Hi How Are you?
I am doing fine!
I need to go now?
I will see you tomorrow!
Basically I need to replace the entire line containing "doing" with a blank line:
I need to the following output:
Hi How Are you?
I need to go now?
I will see you tomorrow!
Thanks in advance.... (1 Reply)
awk , sed Experts,
I want to remove first and last line after pattern match "vg" :
I am trying : # sed '1d;$d' works fine , but where the last line is not having vg entry it is deleting one line of data.
- So it should check for the pattern vg if present , then it should delete the line ,... (5 Replies)
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)