How to assign record count of isql output to a shell variable ?
Quote:
Originally Posted by vidyadhar85
Actually with this option, the variable gets the value like '(1 row affected)' or '(0 rows affected)'. But i need only the exact record count. How to achieve this..?
Hi,
I am giving a grep command, and i am getting the output. i want to store it in a variable
for eg
a = grep '12345' /dir/1/2/log.txt ( the output is number)
b= grep 'basic' /dir/1/2/log1.txt (in this case the output is character)
so how to assign the output of grep to a variable
... (1 Reply)
Hi Guys !
I am new to unix and want to find out how we can make sql statement data to shell script variable?
Any help/suggestion is greatly appreciated
-Chandra (1 Reply)
Hi Guys,
Need help. I am using ISQL inside a shell script.
Is there a way to set the value of shell script variable from inside the ISQL code. I do not want to write the results from the SQL to an output file.
Please let me know.
Regards,
Tipsy. (3 Replies)
What I am trying to do is check if the database query returned any records.
If no records returned then output a message else output results to a file.
Right now if I take out the if and else statements the code runs fine and sends the email. If no records returned the email sends the column... (4 Replies)
Hi All-
First time using iSql.
I have 4 query files - some have more than 1 line of sql statements
After a bit of research it appears I can just use the -i command and specify the input file.
Questions:
Does it matter that there are multiple queries in each file? Do I need to have... (3 Replies)
Hello,
I am writing a ksh script on an AIX system. I need to get the date and time from a file into a variable. I found the following perl script from another post on this site and modified it slightly to output the format I need:
perl -e '@d=localtime ((stat(shift)));... (4 Replies)
Hi ,
I want to use shell variable in isql.
example..
$ksh ./sudh.ksh "2041qwer"
sudh.ksh is my script passing the perameter "2041qwer"
Code in my script :
===========
$SYBASE/$SYBASE_OCS/bin/isql -I$SYBASE/interfaces -S$OTHRSRVR -U$SYBUSER -P$SYBPASS -w... (1 Reply)
I want output to be assigned to UNIX variables
echo "Enter RRS ID: "
read rrs
isql -SPROD_DDS -USYBUSER -PSYBPASS -b -osfg.out << EOF
use sip
go
set nocount on
select issuerId,
legalStructTxt,
productName,
issuerName
from sf_product
where rrsId = $rrs
go
EOF (1 Reply)
Hello,
I have a shell script where I am doing an isql to select some records. the result i get from the select statement is directed to an output file. I want to assign the result to a Shell variable so that I can use the retrieved in another routine.
e.g.
"isql -U${USER} -P${PASSWD} -S${SERVER}... (1 Reply)
I am trying to run a query which returns a sum value(a number).
I want to get it in a variable so that i can refer to that variable in different places.
when i am running the following command
variable=`isql -Uuser -Sserver -Ppassword
1> select sum(count(*)) from xyz..abc where clm_id... (2 Replies)
Discussion started by: Sharma331
2 Replies
LEARN ABOUT DEBIAN
shell-quote
SHELL-QUOTE(1p) User Contributed Perl Documentation SHELL-QUOTE(1p)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)