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Top Forums Shell Programming and Scripting replace a single quote using sed command. Post 302421350 by prachifun on Friday 14th of May 2010 06:57:47 AM
Old 05-14-2010
command that did the work..

I need not have escape charachters before each.

I just need it before '*'.

As * signify that consider 'all data' after the sign.

The command that worked is below.

sed "s/= '\*'/= '^'/g" filename.sh

i used double quote to start the search, so thus I dont need to add '\' to the single quotes.
 

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LESSECHO(1)						      General Commands Manual						       LESSECHO(1)

NAME
lessecho - expand metacharacters SYNOPSIS
lessecho [-ox] [-cx] [-pn] [-dn] [-mx] [-nn] [-ex] [-a] file ... DESCRIPTION
lessecho is a program that simply echos its arguments on standard output. But any argument containing spaces is enclosed in quotes. OPTIONS
A summary of options is included below. -ox Specifies "x" to be the open quote character. -cx Specifies "x" to be the close quote character. -pn Specifies "n" to be the open quote character, as an integer. -dn Specifies "n" to be the close quote character, as an integer. -mx Specifies "x" to be a metachar. -nn Specifies "n" to be a metachar, as an integer. -ex Specifies "x" to be the escape char for metachars. -fn Specifies "n" to be the escape char for metachars, as an integer. -a Specifies that all arguments are to be quoted. The default is that only arguments containing spaces are quoted. SEE ALSO
less(1) AUTHOR
This manual page was written by Thomas Schoepf <schoepf@debian.org>, for the Debian GNU/Linux system (but may be used by others). Send bug reports or comments to bug-less@gnu.org. Version 444: 09 Jun 2011 LESSECHO(1)
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